Question

2 Points What is the center of the circle given by the equation (x+ 5)^2 + (y-8)^2 = 1?

Answer 1

Answer:

(- 5, 8 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 5)² + (y - 8)² = 1 ← is in standard form

with centre (h, k ) = (- 5, 8 )