2 Points
What is the center of the circle given by the equation (x+ 5)^2 + (y-8)^2 = 1?
1 answer:
Answer:
(- 5, 8 )
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x + 5)² + (y - 8)² = 1 ← is in standard form
with centre (h, k ) = (- 5, 8 )
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