2 Points What is the center of the circle given by the equation (x+ 5)^2 + (y-8)^2 = 1?

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

5 0

Answer:

(- 5, 8 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 5)² + (y - 8)² = 1 ← is in standard form

with centre (h, k ) = (- 5, 8 )

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