If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
Answer: 20.52
Step-by-step explanation:
Your welcome
Answer:
87 2/10 km^2. hope it's helpful
Step-by-step explanation:
area = l X w
= 8 km X 10 9/10 km
= 8 X 109/ 10 km^2
= 872/10 km^2
The number 144 is rational because it can be expressed by 144/1
