The standard error of the difference of sample means is 0.444
From the complete question, we have the following parameters
<u>Canadians</u>
- Sample size = 50
- Mean = 4.6
- Standard deviation = 2.9
<u>Americans</u>
- Sample size = 60
- Mean = 5.2
- Standard deviation = 1.3
The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.
This is represented as:
The standard error of the Canadian sample is:
So, we have:
The standard error of the American sample is:
So, we have:
The standard error of the difference of sample means is then calculated as:
This gives
Take square roots
Hence, the standard error of the difference of sample means is 0.444
Read more about standard errors at:
brainly.com/question/6851971
Answer:
D
Explanation:
idk but I'm pretty sure it's D
The concentration of hypochlorite ion if 20.00 ml of bleach requires 32.00 ml of 0.500 m hcl to reach the equivalence point is: 0.800 M.
<h3>
Concentration of hypochlorite ion</h3>
Given:
Ca = concentration/molarity of acid=0.500 M
Va = volume of acid= 32.00 cm3
Cb = concentration/molarity of base=?
VB =volume of base= 20.00 cm3
Hence:
Concentration of hypochlorite ion=0.500 × 0 × 1/ 20.00
Concentration of hypochlorite ion=0.800M
Inconclusion the concentration of hypochlorite ion if 20.00 ml of bleach requires 32.00 ml of 0.500 m hcl to reach the equivalence point is: 0.800 M.
Learn more about Concentration of hypochlorite ion here:brainly.com/question/14038782
brainly.com/question/8527209
By using the F4 function. Second, click the down arrow button in “Size” group under “Format” tab to open the “layout” dialog box. In the dialog box open, change the height and width as you need first. Then clear the “Lock aspect ratio” and “Relative to original picture size” boxes in “Scale” part. Lastly, click “OK”.
