我沒有看到問題?如果您可以在此問題上發布問題,那將非常有幫助!
Was this in reference to literal audio archives? If so, I don't see any cons beside possible copyright infringement.
If you're talking about the codecs themselves, then I can do that.
<span>Pros:
</span>- Widespread acceptance. Supported in nearly all hardware devices, and continually adopted by newer ones.
- Faster decoding. Much more so than FLAC, Vorbis, etc.
- Relaxed licensing schedule.
<span>Cons:
</span><span>
</span>- Lower quality and efficiency than most modern codecs. (To be fair, never really noticed this one).
- Sometimes the maximum bitrate isn't enough.
- Pretty much void/unusable for high definition audio (higher than <span>48kHz).</span>
D. It is used to add sound effects.
Hope this helps!
Answer:
Following are the code to the given question:
user_num = int(input())#defining a variable user_num that takes input from user-end
x = int(input())#defining a variable x that takes input from user-end
for j in range(3):#defining for loop that divides the value three times
user_num = user_num // x#dividing the value and store integer part
print(user_num)#print value
Output:
2000
2
1000
500
250
Explanation:
In the above-given program code two-variable "user_num and x" is declared that inputs the value from the user-end and define a for loop that uses the "j" variable with the range method.
In the loop, it divides the "user_num" value with the "x" value and holds the integer part in the "user_num" variable, and prints its value.