Question

How would the domain and range of the function

Answer 1

Answer:

Domain and range both $(-\infty, \infty)$

Step-by-step explanation:

The range is determined by finding the domain of the inverse of the function(if it has one, in this case it does). The domain is easily determined, because $x$ can obviously range from $(-\infty, \infty)$ without restriction.

The inverse of the function can be found as such:

$x=(1/4)f^{-1}(x)-6\\x+6=(1/4)f^{-1}(x)\\4(x+6)=f^{-1}(x)\\f^{-1}(x)=4x+24$.

Here, $x$ can also range from $(-\infty, \infty)$ without restriction.

So, the domain and range are both $\boxed{(-\infty, \infty)}$