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3 years ago

7

Lainey se desliza por un tobogán de agua de 352 pies de largo a una velocidad de 44 pies por segundo . ¿Cuánto tiempo le tomará

a Lainey viajar desde la parte superior hasta la parte inferior del tobogán?
A -8 segundos
B.
8 segundos
C.
308 segundos
D.
-308 segundos

1 answer:

andre [41]3 years ago

3 0

The awnser to this is -8

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What is the total price of a $40 item including 6.5% sales tax

OverLord2011 [107]

$39.935 is the answer I calculated, but it could very easily be wrong

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3 years ago

An architect built a scale model of a sports stadium using a scale in which 2 inches represents 30 feet. The height of the sport

bija089 [108]

The height of the model in inches would be 6. if you multiply 30 until it reaches 180 you will have 6.

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2 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

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Express each number in its simplest radical form. <br> √6⋅√60=?

Tom [10]

Answer:

6√10

Step-by-step explanation:

factorizing 6 and 60

6 = 2 x 3

60 = 2 x 2 x 3 x 5

hence

√6 · √60

= √ [ (2 x 3) · (2 x 2 x 3 x 5) ]

= √ (2· 2² · 3² · 5)

= √ (2² · 3²) x √(2·5)

= (2 · 3) x √10

= 6√10

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2 years ago

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ANY HELP IS APPRECIATED YALL! PLEASE HELP A GIRL OUT :D THANK YOU FOR TAKING YOUR TIME TO HELP ME:)

nignag [31]

D. 180/4=45. That’s the distance in an hour. Then multiply that by 8.

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2 years ago

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