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abruzzese [7]
3 years ago
8

Which number line represents the solution to the inequality below? *PLEASE ANSWER AND SHOW ALL WORK*

Mathematics
1 answer:
vredina [299]3 years ago
4 0
The answer to this would be B

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write the equation of the line in slope - interact firm given the slop and the coordinates of the y-intercept. m=3/5; (0,1/6)
brilliants [131]
Y - y₁ = m(x - x₁)
y - ¹/₆ = ³/₅(x - 0)
y - ¹/₆ = ³/₅(x) - ³/₅(0)
y - ¹/₆ = ³/₅x - 0
<u>  + ¹/₆         + ¹/₆
</u>       y = <u><em /></u><em />³/₅x + ¹/₆
       y = ³/₅(0) + ¹/₆
       y = 0 + ¹/₆
       y = ¹/₆
5 0
3 years ago
Read 2 more answers
Aquarius is an underwater ocean laboratory located in the Florida keys national marine sanctuary. Solve the equation 31/25x = -6
serg [7]

Answer:

x=-50

Step-by-step explanation:

31/25x=-62

x=-62/(31/25)

x=(-62/1)(25/31)

x=--1550/31

x=-50

4 0
3 years ago
MATCH THE NUMBER ( WORD) TO THE CORRECT DEFINITION (LETTER)
Shtirlitz [24]
1. c
2. e
3. c
4. a
5. b
6 0
4 years ago
The diameter of a sphere with a volume of 12,348 cubic ft is ___ ft.
aniked [119]

Answer:

108.62ft

Step-by-step explanation:

12348=⁴/3×3.14×r²

r²=12348×¾÷3.14

r²=2,949.36

r=squareroot of 2,949.36

r=54.308

d=2r

d=54.308×2

d=108.616

6 0
3 years ago
The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in
Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 64 inches

           \sigma = standard deviation = 4 inches

           n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{63-64}{\frac{4}{\sqrt{4} } } ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

                                                        = 1 - 0.69146 = 0.30854

Hence, it is 30.85%  likely that average height would be shorter than 63 inches.

7 0
4 years ago
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