Y - y₁ = m(x - x₁)
y - ¹/₆ = ³/₅(x - 0)
y - ¹/₆ = ³/₅(x) - ³/₅(0)
y - ¹/₆ = ³/₅x - 0
<u> + ¹/₆ + ¹/₆
</u> y = <u><em /></u><em />³/₅x + ¹/₆
y = ³/₅(0) + ¹/₆
y = 0 + ¹/₆
y = ¹/₆
Answer:
x=-50
Step-by-step explanation:
31/25x=-62
x=-62/(31/25)
x=(-62/1)(25/31)
x=--1550/31
x=-50
Answer:
108.62ft
Step-by-step explanation:
12348=⁴/3×3.14×r²
r²=12348×¾÷3.14
r²=2,949.36
r=squareroot of 2,949.36
r=54.308
d=2r
d=54.308×2
d=108.616
Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.