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ivann1987 [24]
3 years ago
7

Wolfman and Dracula we’re having a contest to see who can scare people the most for every three people Dracula scare Wolfman sca

red seven if Wolfman scared 24 more people how many people were scared and all
Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0
So um i to get a new phone with him to help me with my work schedule and then i i to get my money on my way back from work so i’ll give him my bath now i and i and my mom works at the house for me a few days and i to see if he wants me a friend and 728
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The pinata weighs 11/4 pounds without candy.He adds 8bags that weighs 3/8,3/8,1/2,1/2,1/2,3/4,3,11/4 how much will the pinata we
Natalka [10]

Answer:

Weight = \frac{23}{2}

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

Candies =  \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}

Take LCM

Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}

Candies = \frac{70}{8}

Simplify:

Candies = \frac{35}{4}

Next; Add the weight of the candies to the weight of pinata

Weight = Candies + Pinata

Weight = \frac{35}{4} + \frac{11}{4}

Take LCM

Weight = \frac{35 + 11}{4}

Weight = \frac{46}{4}

Simplify

Weight = \frac{23}{2}

<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>

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3 years ago
abby makes two different quilts. Each quilts is a square. However, the quilts have diferent perimeter, and areas. Describe the a
Ostrovityanka [42]
I would answer this question if I had a picture or something to guide me
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3 years ago
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ASAP JUST WORK NO ANSWER
Romashka-Z-Leto [24]
This is not a function but the domain is x and the range is going to y so the first is the domain and the second box it the range
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an eraser company needs to ship erasers in bags of 780 plus or minus 9 erasers. what is the minimum and maximum erasers that cou
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Answer:

the minimum is 771 erasers while the maximum is 789 erasers

Step-by-step explanation:

5 0
3 years ago
Can someone help me find the answer to this problem 2(x-3)=14
lord [1]

Answer:4

Step-by-step explanation:

2x-6=14

2x=8

x=4

5 0
2 years ago
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