All categories

2 years ago

14 = 31.7 – 3x What is the solution

Mathematics

2 answers:

netineya [11]2 years ago

4 0

14 = 31.7 - 3x
-17.7 = -3x
x = 5.9

Darya [45]2 years ago

4 0

31.7 - 3x = 14
subtract 31.7 from both sides
-17.7 = -3x
divide both sides by -3
5.9 = x

your answer is 5.9

You might be interested in

Complex to Trigonometric:<br>Z=√6+√2+2i

Alekssandra [29.7K]

Answer:

z=6+2i maybe

Step-by-step explanation:

8 0

3 years ago

A person places $81200 in an investment account earning an annual rate of 3.6%, compounded continuously. Using the formula V = P

dolphi86 [110]

Answer:

V=129659.9491≈129659.95

Step-by-step explanation:

4 0

2 years ago

Earth is approximately 9.3 × 10^7 miles from the sun and Saturn is approximately 8.87 × 10^8 miles from the sun. Approximately h

denis23 [38]

Answer:

7.94 x 10⁸miles

Step-by-step explanation:

Given parameters:

Distance of earth from sun = 9.3 x 10⁷miles

Distance of earth from Saturn = 8.87 x 10⁸miles

Unknown:

How much further from the sun is Saturn than Earth = ?

Solution:

To find the solution to this problem, let us find the difference between their distances:

( 8.87 x 10⁸ miles - 9.3 x 10⁷ miles )

= 88.7 x 10⁷ miles - 9.3 x 10⁷ miles

= (88.7 - 9.3) x 10⁷miles

= 79.4 x 10⁷miles

= 7.94 x 10⁸miles

8 0

3 years ago

Write the first three terms of the series for which tn = 2(n+3). Find the number of terms of the series required to make the sum

ira [324]

Answer:

The first three terms of the series are 8, 10 and 12. The number of terms is 12 to make the sum 228.

Step-by-step explanation:

The series is defined as

$t_n=2(n+3)$

Put n=1.

$t_1=2(1+3)=2\times 4=8$

Put n=2.

$t_2=2(2+3)=2\times 5=10$

Put n=3.

$t_3=2(3+3)=2\times 6=12$

The first three terms of the series are 8, 10 and 12.

It is an arithmetic series. The first terms is 8 and the common difference is

$d=a_2-a_1=10-8=2$

The sum of n terms of an arithmetic series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$288=\frac{n}{2}[2(8)+(n-1)2]$

$288=\frac{2n}{2}[8+n-1]$

$288=n[n+7]$

$0=n^2+7n-288$

$0=n^2+19n-12n-288$

$0=n(n+19)-12(n+19)$

$0=(n+19)(n-12)$

Equate each factor equal to zero.

$n=-19,12$

The number of terms can not be negative, therefore the value of n must be 12.

6 0

3 years ago

WRITE AN EQUATION

dimaraw [331]

Answer:

54 students

Step-by-step explanation:

331 - 7

= 324

324 ÷ 6

= 54 students

7 0

2 years ago