SA = 2
+2

1. Find the radius.
R = 1/2D
6 x 1/2 = 3
R = 3
2. Plug them in.
SA 2(3.14)(3)(7) + 2(3.14)(3^2)
3. Solve
3 x 7 = 21
21 x 3.14 = 65.94
65.94 x 2 = 131. 88
3^2 = 9
9 x 3.14 = 28.26
28.26 x 2 = 56.52
4. Add them together.
131.88 + 56.52 = 188.4
Answer: 188.4 square millimeters
22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
X=3; you can set up a proportion using the slope equation. So (y[sub2]-y[sub1])/(x[sub2]-x[sub1])=2/1 then plug in the values and simplify. Then cross multiply and solve for x. Rest of work shown in the picture
Answer: A & C
Step-by-step explanation: A. Two parallel lines are coplanar.
C. Two planes that do not intersect are parallel.
Answer:
The surface area of the cone is 126π cm².
Step-by-step explanation:
The surface area of a cone can be found using this formula:

- where r = radius and l = slant height
In this problem, we are told that the cone has a radius of 9 cm and a slant height of 5 cm.
Substitute these values into the formula for the surface area of a cone.
The surface area of the right cone is 126 π cm².