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2 years ago

Will give brainliest.

Mathematics

2 answers:

Anon25 [30]2 years ago

4 0

Answer:

4 days is the correct answer

Step-by-step explanation:

tigry1 [53]2 years ago

4 0

Answer:

4 days

Step-by-step explanation:

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Last year, the school library had a total of x books. Over the summer, the library acquired another 35 books and now has a total

ki77a [65]

Answer:

the equation is x= 2908

Step-by-step explanation:

you need to find the number of books they had by taking the new total and subtract it by the number they add and that would equal x in the problem

6 0

3 years ago

A recent survey of 8,000 high school students found that the mean price of a prom dress was $195.00 with a standard deviation of

KiRa [710]

To calculate the z-statistic, we must first calculate the standard error.

Standard error is standard deviation divided by the square root of the population. In this case, it is equal to 2.68.

The z-score is defined the distance from the sample to the population mean in units of standard error.

z = (195 – 208)/2.68 = -4.86

5 0

3 years ago

Which value makes the equation true?<br><br><br><br> □+0.34=2.34

Nataly [62]

Answer:

2.00

Step-by-step explanation:

let the empty box be the variable n. n+0.34=2.34

subtract .34 from both sides

n=2.00

8 0

2 years ago

Read 2 more answers

Consider an angle with a measure of θ=225∘.

wel

Answer:

cos 225° = $-\frac{\sqrt{2} }{2}$

sin 225° = $-\frac{\sqrt{2} }{2}$

tan 225° = 1

Step-by-step explanation:

I cannot sketch a diagram, but a 225° angle is a 3rd quadrant angle and the reference angle is 45° (225 - 180 = 45)

cos and sin are negative in the 3rd quadrant and the tan is positive

cos 225° = - cos 45° = $-\frac{\sqrt{2} }{2}$

sin 225° = -sin 45° = $-\frac{\sqrt{2} }{2}$

tan 225° = tan 45° = 1

8 0

2 years ago

Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.

Gekata [30.6K]

Take the augmented matrix,

$\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]$

Swap the row 1 and row 2:

$\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]$

Add -2(row 1) to row 2, and -1(row 1) to row 3:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]$

Multiply through row 3 by 1/9:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]$

Add 5(row 3) to row 2:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]$

Multiply through row 2 by -1/3:

$\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]$

Add -2(row 2) and -1(row 3) to row 1:

$\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]$

So we have $\boxed{x=-3,y=-2,z=4}$ .

3 0

3 years ago