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Roman55 [17]
2 years ago
15

Will give brainliest.

Mathematics
2 answers:
Anon25 [30]2 years ago
4 0

Answer:

4 days is the correct answer

Step-by-step explanation:

tigry1 [53]2 years ago
4 0

Answer:

4 days

Step-by-step explanation:

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Last year, the school library had a total of x books. Over the summer, the library acquired another 35 books and now has a total
ki77a [65]

Answer:

the equation is x= 2908

Step-by-step explanation:

you need to find the number of books they had by taking the new total and subtract it by the number they add and that would equal x in the problem

6 0
3 years ago
A recent survey of 8,000 high school students found that the mean price of a prom dress was $195.00 with a standard deviation of
KiRa [710]

To calculate the z-statistic, we must first calculate the standard error.

Standard error is standard deviation divided by the square root of the population. In this case, it is equal to 2.68.

The z-score is defined the distance from the sample to the population mean in units of standard error.

z = (195 – 208)/2.68 = -4.86

5 0
3 years ago
Which value makes the equation true?<br><br><br><br> □+0.34=2.34
Nataly [62]

Answer:

2.00

Step-by-step explanation:

let the empty box be the variable n. n+0.34=2.34

subtract .34 from both sides

n=2.00

8 0
2 years ago
Read 2 more answers
Consider an angle with a measure of θ=225∘.
wel

Answer:

cos 225° = -\frac{\sqrt{2} }{2}

sin 225° = -\frac{\sqrt{2} }{2}

tan 225° = 1

Step-by-step explanation:

I cannot sketch a diagram, but a 225° angle is a 3rd quadrant angle and the reference angle is 45°   (225 - 180 = 45)

cos and sin are negative in the 3rd quadrant and the tan is positive

cos 225° = - cos 45° = -\frac{\sqrt{2} }{2}

sin 225° = -sin 45° = -\frac{\sqrt{2} }{2}

tan 225° = tan 45° = 1

8 0
2 years ago
Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

3 0
3 years ago
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