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3 years ago

What is an equation for the line that passes through points (8, -3) and (9, 10)

Mathematics

1 answer:

34kurt3 years ago

3 0

Answer:

y=13x-107

Step-by-step explanation:

(10- -3)/(9-8)=13

10=13*9+b

b=10-117=-107

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Please answer this in two minutes

Sunny_sXe [5.5K]

Answer:

D. 1800°

Step-by-step explanation:

The given polygon has 12 sides.

The formula for finding the sum of the interior angles of an n-sided polygon is given as, ( n − 2 ) × 180.

Where n is the number of sides of the polygon.

Thus, the sum of the interior angles of the 12 sided polygon given above is:

(12 - 2) × 180

= 10 × 180 = 1800°

<em>Sum of the measures of the interior angles of the 12-sided polygon is D. 1800°</em>

4 0

3 years ago

a room has a length of 11 ft if the room has an area of at least 133 ft what does the width of the room have to be at least

MissTica

Area is the length times the width.

When you know the area and one of the dimensions, divide the area by the known dimension to find the other one.

133 / 11 = 12.09

The room needs to be at least 12.09 feet wide. ( round answer if needed).

7 0

3 years ago

I dont understand anything

Leviafan [203]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago

Pete can buy daffodil bulbs in packages of 3 for $6.39 or in packages of 2 for $4.40. How much money does he save by buying 30 b

tatyana61 [14]

Answer:

The correct answer is Pete saves $2.10 by buying bulbs in packages of 3 for $6.39 each.

Step-by-step explanation:

Pete can buy daffodil bulbs in packages of 3 for $6.39 or in packages of 2 for $4.40.

He needs to buy 30 bulbs at a better price.

Money spent by buying bulbs in packs of 3 = 10 × 6.39 = $63.90.

Money spent by buying bulbs in packs of 2 = 15 × 4.40 = $66.

Money saved if bought in packs of 3 = 66 - 63.90 = $ 2.10.

Thus Pete should buy 30 daffodil bulbs in packages of 3 and save $2.10.

7 0

3 years ago