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IRISSAK [1]
3 years ago
6

What is an equation for the line that passes through points (8, -3) and (9, 10)

Mathematics
1 answer:
34kurt3 years ago
3 0

Answer:

y=13x-107

Step-by-step explanation:

(10- -3)/(9-8)=13

10=13*9+b

b=10-117=-107

You might be interested in
Which three lengths could be the lengths
Fed [463]

Given:

The three lengths in the options.

To find:

Which three lengths could be the lengths of the sides of a triangle?

Solution:

If the sum of two smaller sides is greater than the largest side, then the three sides can form a triangle otherwise the triangle is not possible.

In option A, the three sides are 4 cm, 8 cm, 13 cm. Here, the largest side is 13 cm.

Sum of two smaller sides is:

4+8=12

4+8

So, the triangle is not possible.

In option B, the three sides are 13 cm, 11 cm, 23 cm. Here, the largest side is 23 cm.

Sum of two smaller sides is:

13+11=24

13+11>23

So, the triangle is possible.

In option C, the three sides are 5 cm, 18 cm, 12 cm. Here, the largest side is 18 cm.

Sum of two smaller sides is:

5+12=17

5+12

So, the triangle is not possible.

In option D, the three sides are 25 cm, 8 cm, 16 cm. Here, the largest side is 25 cm.

Sum of two smaller sides is:

8+16=24

8+16

So, the triangle is not possible.

Therefore, the correct option is B. The three lengths 13 cm, 11 cm, 23 cm could be the lengths of the sides of a triangle.

6 0
2 years ago
Using elimination, what is the solution to the following system?<br> 2x+4y=16<br> -2x-3y=-13
VikaD [51]

Answer:

x=2, y=3. (2, 3).

Step-by-step explanation:

2x+4y=16

-2x-3y=-13

-----------------

y=3

2x+4(3)=16

2x+12=16

2x=16-12

2x=4

x=4/2

x=2

8 0
2 years ago
Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x
Natali [406]

Answer: hello your question is incomplete attached below is the complete question

answer :

a)   \int\limits^3_0 {(10-x)-(x+4)} \, dx     ( option D )

b) A =  1/2 (6)(3)   ( option B )

c) Area of shaded region = 9

Step-by-step explanation:

<u>a) Using integration with respect to x </u>

Area =   \int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy         ( note a = 10 )

          = y^2/2 - 4y |⁷₄  + 10y - y^2/2 |¹⁰₇

          = 33/2 - 12 + 30 - 51/2   = 9

hence the best integral from the options attached is option D

\int\limits^3_0 {(10-x)-(x+4)} \, dx

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

= 30 - 9/2 - 9/2 - 12  = 9

<u>b) Using Geometry </u>

Area = 1/2 * base * height

        = 1/2 * 6 * 3

        = 9

7 0
3 years ago
Can someone please help me and explain? please
mariarad [96]
Composite figure is made up of 4 triangles and a square.

Area of Square = Length x Length 
Area of Square = 12 x 12
Area of Square= 144 cm²

Area of triangle = 1/2 x base x height
Area of triangle  = 1/2 x 12 x 8 
Area of triangle  = 48 cm²

Area of 4 Triangles = 48 x 4
Area of 4 Triangles = 192 cm²

Total Area = 144 + 192 = 336 cm² 

\Longrightarrow \boxed { \boxed { Answer : 336 cm^{2} }}


4 0
3 years ago
Pls help with sum geometry
kaheart [24]

YES! quite easily.

I hope you can see the two pairs of corresponding angles between the parallel lines. they'll be equal

and then there's a pair of vertically opposite angle at centre.

that means all pairs of corresponding angles are equal, thus, triangles are similar by AAA

4 0
3 years ago
Read 2 more answers
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