Answer:
The required probability is 0.167
Step-by-step explanation:
Consider the provided information.
Let x be the number of breakdown per day.
A new automated production process averages 1.4 breakdowns per day.
λ=1.4
Probability of having three or more breakdowns during a day is:
![P(x\geq 3)=1-[f(0)+f(1)+f(2)]](https://tex.z-dn.net/?f=P%28x%5Cgeq%203%29%3D1-%5Bf%280%29%2Bf%281%29%2Bf%282%29%5D)
The Poisson probability function is: 
Therefore the required probability is:
![P(x\geq 3)=1-[\frac{\left(1.4^{0}e^{-1.4}\right)}{0!}+\frac{\left(1.4^{1}e^{-1.4}\right)}{1!}+\frac{\left(1.4^{2}e^{-1.4}\right)}{2!}]](https://tex.z-dn.net/?f=P%28x%5Cgeq%203%29%3D1-%5B%5Cfrac%7B%5Cleft%281.4%5E%7B0%7De%5E%7B-1.4%7D%5Cright%29%7D%7B0%21%7D%2B%5Cfrac%7B%5Cleft%281.4%5E%7B1%7De%5E%7B-1.4%7D%5Cright%29%7D%7B1%21%7D%2B%5Cfrac%7B%5Cleft%281.4%5E%7B2%7De%5E%7B-1.4%7D%5Cright%29%7D%7B2%21%7D%5D)
Hence, the required probability is 0.167
Answer:
£69
Step-by-step explanation:
Given information:
- Cost of dress = £50
- Cost of shoes = £43
- Discount offer: Buy a dress and shoes together and get 1/3 off the price.
- Shipping & handling charge = £7 (added after the discount is applied)
Cost of buying a dress and shoes:
⇒ £50 + £43 = £93
Discount:
⇒ 1/3 of £93 = 1/3 × 93 = £31
Cost of goods after discount is applied:
⇒ £93 - £31 = £62
Addition of shipping and handling:
⇒ £62 + £7 = £69
Therefore, Ruth will pay £69 if she buys a dress and shoes.
Answer:
Neither even or odd
Step-by-step explanation:
Parellel would mean that it's the same slope, so it's one of the first three. Checking each of them individually, we see that the first one, when you plug in 3, results in 1, getting (3,1)!
