<span>The domain of the function can be obtained by pluging the values of the range into f(x), i.e domain = {k^2 + 2k + 1 = 25, k^2 + 2k + 1 = 64} = {k^2 + 2k - 24 = 0, k^2 + 2k - 63 = 0}. Solving the two quadratic equations, we have that the range is {-9, -6, 4, 7}.I hope that my answer is helpful! Let me know if you need something more :)</span>
I can see why your confused, but the range of the function is <u>y≤−1 or y≥1</u> . The graph of the cotangent function looks like this: The domain of the function <u>y=cot(x)=cos(x)sin(x)</u> is all real numbers except the values where <u>sin(x)</u> is equal to 0 , that is, the values <u>πn for all integers n</u> .
<em>Hope this helps</em>
Have a great day!
<h3>-~- <u>WolfieWolfFromSketch</u> -~-</h3>
Is equal to 19 u add the 9 plus the ten so u get 19
Answer:
468
Step-by-step explanation:
8/4*234=2*234=468