solution:
P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68
hence probability that she was enrolled in Dr. J's section given passed
=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706
All you have to do is:
Make all of your fractions to common denominator.
Then, you add 8 3/10-1 2/5- 2 1/3+ 4 3/5
And when you solve it, you get 9 5/30 and when you simplify it,
You get 9 1/6 yards of ribbon
Answer:
We know our answer is correct because 11 + 12 + 13 equals 36 as displayed Below
Explanation
3X + 3 = 36 3X + 3 - 3 = 36 - 3 3X = 33 3X/3 = 33/3 X = 11 Which means that the first number is 11, the second number is 11 + 1 and the third number is 11 + 2. Therefore, three consecutive integers that add up to 36 are 11, 12, and 13. 11 + 12 + 13 = 36 We know our answer is correct because 11 + 12 + 13 equals 36 as displayed above. Therefore, three consecutive integers that add up to 36 are 11, 12, and 13. 11 + 12 + 13 = 36
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