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QveST [7]
3 years ago
12

Find the range of the function: f(x) = x + 3, for x ≠ 1

Mathematics
1 answer:
Tju [1.3M]3 years ago
3 0

Answer:

All Real Numbers except for 4

Step-by-step explanation:

Objective: Specify domain and range of a function.

The equation is a linear equation. A linear equation range is all real numbers. However x cannot equal 1 so let plug in x to find where the y value CANT be.

f(1) = 1 + 3 = 4

So the range is

All Real Numbers except for 4.

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True or false A triangle with sides having measures of 3, 4,
Fofino [41]

Answer:

False

Step-by-step explanation:

A commonly known Pythagorean Triple for a right triangle is a 3-4-5 triangle.  Something so close will not be a perfect right triangle, but may be close.

6 0
3 years ago
Read 2 more answers
A savings account for a car is set up with an initial balance of $1500, and 250 is added every month (no other
pychu [463]

Answer:

ok so first we subtract 1500

5000-1500=3500

3500 divided by 250= 14

So it will take 14 months

Hope This Helps!!!

8 0
3 years ago
Which graph represents y= square root x-4
wolverine [178]

Answer:

Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain.Domain: [4,∞),{x|x≥4}[4,∞),{x|x≥4}Range: [0,∞),{y|y≥0}

8 0
2 years ago
Lindsey is considering purchasing an item that costs $860 and has a discount of 15 % . What is the amount of discount on
Blizzard [7]

Answer:

$129

Step-by-step explanation:

We need to find 15% of $860.

15% of $860 =

= 15% * $860

= 0.15 * $860

= $129

4 0
3 years ago
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
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