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sveta [45]
2 years ago
9

How are same side interior angles related to one another?​

Mathematics
2 answers:
tia_tia [17]2 years ago
8 0

Answer:

The relation between the same side interior angles is determined by the same side interior angle theorem. The theorem for the "same side interior angle theorem" states: If a transversal intersects two parallel lines, each pair of same-side interior angles are supplementary (their sum is 180°).

MA_775_DIABLO [31]2 years ago
8 0

Answer:

∠A+∠B+∠C=180°

Step-by-step explanation:

You might be interested in
All the items on the sale rack were 75 percent off their original price.
tresset_1 [31]

Answer:

112 $ is the original price

Step-by-step explanation:

x \times 0.75 = 84 \\ x = 84 \div 0.75 \\ x = 112

you have to think that the original price multiplied by 0.75 (also known as 75%) gave the result of what he saves i.e 84 $. So we put up an equation with the original price multiplied by 75% which equals the 84 $ he saved on buying that item on sale

4 0
3 years ago
What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n
Yakvenalex [24]

Answer:

(\sqrt{2},-1),(-\sqrt{2},-1)

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

-2x^{2} +y=-5 ----> equation A

y=-3x^{2} +5 -----> equation B

solve by substitution

substitute equation B in equation A

-2x^{2} +(-3x^{2} +5)=-5

solve for x

-5x^{2} +5=-5

-5x^{2}=-10

x^{2}=2

x=\pm\sqrt{2}

<em>Find the value of y</em>

y=-3x^{2} +5

For x=\sqrt{2} ----> y=-3(\sqrt{2})^{2} +5=-1

For x=-\sqrt{2} ----> y=-3(-\sqrt{2})^{2} +5=-1

therefore

The solutions are

(\sqrt{2},-1),(-\sqrt{2},-1)

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

8 0
3 years ago
Read 2 more answers
Helpppppp asapppppopoo
wlad13 [49]
Answer: Choice A

Raising something to the 1/4th power is the same as applying the 4th root to that expression. Raising an expression to the 1/n power is the same as applying the nth root.

Rule:
x^{1/n} = \sqrt[n]{x}
(if the text is too small it basically says x to the (1/n) = square root with a small 'n' all over x)
4 0
2 years ago
20.Les membres de la famille Veilleur sont en vacances, le premier pour, **
mamaluj [8]

Answer:

Quantité totale d'essence consommée:  167 litres (arrondie à l'unité pres)

Nombre de jours du voyage: 12 jours (je pense! Je ne comprends pas "jours sants" ? Suivants? )

Distance parcourue pour aller à Pittsburgh: 1269.8 km

coût total de l'essence: $ 204.11

Coût moyen de l'essence consommée par jour (arrondi au centieme pres): $17.01

Distance parcourue par jour pour le retour:  613.5 km

Distance totale parcourue durant les vacances:​ 2496.8 km

Step-by-step explanation:

Jour 1 Montreal à Parc Sandbanks

2,3,4,5 Parc Provincal Sandbanks

6,7,8,9,10  Pittsburgh

11,12 Pittsburgh à Quebec

Distance: ajouter les numéros jours par jour.

Essence consommée: 6.7 litres pre 100, donc diviser la distance totale par 100  puis multiplier par litres par km

2496.8/100 = 24.968 × 6.7 = 167.2856  et arrondir le total: 167.3

Coût total de l'essence: Il faut multiplier le total consommée par la coût par litre, $1.22  167.3×1.22 = $204.11

Coût moyen de l'essence consommée par jour:  $204.11 ÷ 12 jours = $17.01/jour

Distance parcourue par jour pour le retour: 1227km/2days = 613.5 km/jour

Distance totale parcourue durant les vacances:​ Ajoutez les distances journalières parcourues à Pittsburgh à la distance de retour  à Quebec.

1269.8 + 1227 = 2469.8 km

7 0
2 years ago
Help asap please!! &lt;3
Sergio039 [100]

Answer:

9.3%

Step-by-step explanation:

You are welcome!!

3 0
2 years ago
Read 2 more answers
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