The answer to that question is 1
Complete Question
A biologist reports a confidence interval of (3.5,4.9) when estimating the mean height (in centimeters) of a sample of seedlings. What is the estimated margin of error and the sample mean?
Answer:
The margin of error is 
The sample mean is 
Step-by-step explanation:
from the question we are told that
The upper limit is 
The lower limit is 
Generally the margin of error is mathematically represented as



Generally the sample mean is mathematically evaluated as

=> 
=> 
Answer:
the answer is 100
Step-by-step explanation:
bc it is moved over 2 places to the left, plz can i be brainliest
Answer:
N=115
Step-by-step explanation:
n=.25(2.5715/.12)^2 =114.8 so round up to 115. Hope that help you
Two lines are perpendicular between each other if their slopes fulfills the following property

where m1 and m2 represents the slopes of line 1 an 2, respectively.
To find the slope of a line we can write it in the form slope-intercept form

Our original line is

Then its slope is

Now we have to find the slope of the second line. Using the first property,

Then the second line has to have a slope of 8.
The options given to us are:

Then we have to determine which of these options have a slope of 8. To do that we write them in the slope-intercept form:

Once we have the options in the right form, we note that the only one of them that has a slope of 8 is the last one.
Then the line perpendicular to the original one is