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Identify the terminal point for a 30° angle in a unit circle.

Afina-wow [57]

Answer:

The coordinates for the point on a circle of radius at an angle of are At the radius of the unit circle, 1, serves as the hypotenuse of a 30-60-90 degree right triangle, as shown in (Figure).

Step-by-step explanation:

4 0

2 years ago

Please help !!!!!!!!!

Serggg [28]

Answer:

This is some ton of work LOL

Step-by-step explanation:

A. 4/7×5/5=20/35 We multiply by 5 for A because 35÷5=7 and you need to multiply top and bottom. You can NOT forget that. We do not need to simplify something this time? 3/5X7/7=21/35. Why are we muliplying something new? figure out. no need to simplify. oBVIOUSLY 3/5 IF BIGGER

B. As usual etc...

8 0

3 years ago

(-10)³ * 3 * 2 * (-7 ) <br> Please help

viktelen [127]

Answer:

i think it is 42000 but i could be wrong

Step-by-step explanation:

8 0

2 years ago

What is the capacity of the cube in liters? mid-unit test

Scrat [10]

A hope it helps tell me if I am wrong

3 0

3 years ago

PLEASE HELP.

OverLord2011 [107]

Answer:

Explicit formula for

1) $a_n=17-3(n-1)$

2) $a_n=(\frac{1}{2} )^{n-1}\cdot 20$

Step-by-step explanation:

W have to find the first few terms of the given sequence and then find an explicit equation

Explicit formula = f(n) + d(n-1) , where,

f(n) is first term,

d is common difference,

n-1 is one term less than the term number.

1)

Given : $a_1=17\\\\a_{n+1}=a_n-3$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

2)

Given : $a_1=20\\\\a_{n+1}=\frac{1}{2} \cdot a_n$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

$\text{We put n =1, we get,}\\\\\\a_2=\frac{1}{2} \cdot a_1=\frac{1}{2} \cdot 20=10=(\frac{1}{2} )^{2-1}\cdot 20\\\\\\\text{We put n =3, we get,}\\\\\\a_4=\frac{1}{2} \cdot a_3=\frac{1}{2} \cdot 5=\frac{5}{2}=(\frac{1}{2} )^{4-1}\cdot 20\\\\\\$

Thus, we obtained an explicit formula,

$a_n=(\frac{1}{2} )^{n-1}\cdot 20$

8 0

3 years ago

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