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2 years ago

Help pls, will choose brainliest if explanation is provided

Mathematics

1 answer:

Nookie1986 [14]2 years ago

8 0

Answer:

$solve \: when \: (f + g) \:(4) \\ \\ first \: solve \: for \: f(x) \\ \: \\ solution \: .... \\ \\ f(x) = 4x - 3 \\ f(4) = 4(4) - 3 \\ f(4) = 16 - 3 \\ f(4) = 13 \\ \\ \\ now \: solve \: for \: g(x) \\ \: \\ solution \: .... \\ \\ g(x) = {x}^{3} + 2x \\ g(x) = {(4)}^{3} + 2(4) \\ g(x) = 64 + 8 \\ g(x) = 72 \\ \\ (f) - (g) = 13 - 72 \\ (f) -(g) = -59$

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Ede4ka [16]

Answer:

Hey,

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Wbob1314 hope it helped

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2 years ago

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ELEN [110]

First, you have to add 16 to both sides because it's the opposite of subtracting.
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3 years ago

P=s1+s2+s3 solve for s3

tresset_1 [31]

P=s1+s2+s3

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p-s1-s2=s2-s2+s3

p-s1-s2=s3

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