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3 years ago

(a + 3)(a - 2) hurry helpppp asapppp

Mathematics

2 answers:

mote1985 [20]3 years ago

7 0

(a+3)(a-2)

Multiply the two brackets together

a^2-2a+3a+3*-2

a^2+a-6

Answer is a^2+a-6

DedPeter [7]3 years ago

3 0

ANSWER

${a}^{2} + a - 6$

EXPLANATION

The given expression is

$(a + 3)(a - 2)$

We expand using the distributive property to obtain:

$a(a - 2) + 3(a - 2)$

We multiply out the parenthesis to get:

${a}^{2} - 2a + 3a - 6$

Let us now simplify by combining the middle terms to obtain;

${a}^{2} + a - 6$

You might be interested in

Evaluate the double integral.

Fynjy0 [20]

Answer:

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

Step-by-step explanation:

The equation of the line through the point $(x_o,y_o)$ & $(x_1,y_1)$ can be represented by:

$y-y_o = m(x - x_o)$

Making m the subject;

$m = \dfrac{y_1 - y_0}{x_1-x_0}$

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

$m= \dfrac{2-1}{1-0}$

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

$m = \dfrac{1-2}{4-1}$

$m = \dfrac{-1}{3}$

∴

$y-2 = -\dfrac{1}{3}(x-1)$

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

$\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg) dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ([y^2(-4y+8)] \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( -4y^3+8y^2 \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{-45+56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{11}{3}\bigg]$

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

4 0

2 years ago

Two more than 5 times a number is greater than or equal to 3

jenyasd209 [6]

Answer:

n ≥ 1/5

Step-by-step explanation:

Let the number be n. Then 5n + 2 ≥ 3.

If you want to solve this for n, then subtract 2 from both sides, obtaining:

5n ≥ 1. Isolate n by dividing both sides by 5. Then we have n ≥ 1/5

3 0

3 years ago

Choose whether the expression is a result of multiplying

vladimir1956 [14]

Answer:

neither

Step-by-step explanation:

Take out 5 as a common factor. It will be easier to look at.

5(5c^2 + 11c + 6)

5(5C +6 )(c + 1 )

Now you can put the 5 inside.

(25c + 30)(c + 1) is one answer.

(5c + 6)(5c + 5) is another.

The answer is multiplying binomials. There is nothing that that is squared and the answers are not conjugates. They are two binomials multiplied together.

8 0

2 years ago

Jasper made a flag for his football team. He painted 1/2 of the flag blue and 1/2 of the flag yellow. He added stars to 1/3 of t

SVETLANKA909090 [29]

For this case we have that half of the flag was painted blue and the other half yellow.

In addition, a third of the blue half was covered with stars.

So:

$\frac {1} {2} * \frac {1} {3} = \frac {1} {6}$

A sixth of the flag is blue with stars.

Answer:

$\frac {1} {6}$

6 0

3 years ago

If you lose two lbs a week consuming 600 calories, how many lbs would you lose consuming half of that?

SCORPION-xisa [38]

Answer:

maybe 4

Step-by-step explanation:

Well consider the fact a normal diet is about 1,200 calories a day. half of that is 600, there for you lose 2 pounds in a week. if you cut that in half the chances are you'll loose 4 pounds. but consuming only 300 calories a day is extremely unhealthy

4 0

3 years ago