Answer:
embedded system
Explanation:
Based on the scenario being described within the question it can be said that the type of software that is being described is known as an embedded system. This is actually a combination of both hardware and software that focuses on a specific function which is later implemented into a much larger system to allow it to become "smarter", by performing more complex tasks, which would otherwise not be possible.
Hey there,
I believe that your correct answer would be that "<span> some people will tell you what they think you want to hear </span>". When you ask someone about the perceptions of your person trait, they will most likely <span>tell you what they think you want to hear because its what they want to make you happy.
For example: Jimmy ask billy "Am I fat Billy"
Billy tells Jimmy "No, Your not fat, you look just great".
But really, Jimmy is very fat.
The point is that people are going to say things that make you feel happy and something that you want to hear.
~Jurgen</span>
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Answer:
Explanation:
The following code is written in Python. It is a function called guessMyNumber and like requested creates a random number and saves it to secretNumber. Then it continuously asks the user for their guess and compares it to the secret number. If the guess is correct it exits the loop otherwise it will continue to ask for a new guess.
import random
def guessMyNumber():
secretNumber = random.randint(1, 10)
print(secretNumber)
while True:
guess = input("Enter your guess: ")
guess = int(guess)
if (guess == secretNumber):
print("Congratulations you guessed correctly")
