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ozzi
3 years ago
11

The points H, I, J and K all lie on the same line segment, in that order, such that the

Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Step-by-step explanation:

<em>Given</em><em>,</em>

<em>ratio</em><em> </em><em>of </em><em>HI,</em><em> </em><em>IJ </em><em>,</em><em> </em><em>Jk </em><em>=</em><em> </em><em>2</em><em> </em><em>:</em><em> </em><em>1</em><em> </em><em>:</em><em> </em><em>2</em>

<em>let </em><em>their </em><em>value </em><em>be</em>

<em>HI </em><em>=</em><em> </em><em>2</em><em>x</em>

<em>IJ </em><em>=</em><em> </em><em>x</em>

<em>JK </em><em>=</em><em> </em><em>2</em><em>x</em>

<em>HK </em><em>=</em><em> </em><em>2</em><em>5</em>

<em>according</em><em> </em><em>to </em><em>question</em><em>,</em>

<em>HI </em><em>+</em><em> </em><em>IJ </em><em>+</em><em> </em><em>JK </em><em>=</em><em> </em><em>Hk</em>

<em>now,</em><em> </em><em>after </em><em>inserting</em><em> the</em><em> values</em><em> we</em><em> got</em><em>,</em>

<em>→</em><em> </em><em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em>

<em>→</em><em> </em><em>5</em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em>

<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>2</em><em>5</em><em>/</em><em>5</em><em> </em><em>=</em><em> </em><em>5</em>

<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>5</em>

<em>therefore</em><em> </em><em>value </em><em>of,</em>

<em>HI </em><em>=</em><em> </em><em>2</em><em>x</em><em> </em><em>→</em><em> </em><em>2</em><em>×</em><em>5</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em>

<em>IJ </em><em>=</em><em> </em><em>x </em><em>→</em><em> </em><em>5</em>

<em>JK </em><em>=</em><em> </em><em>2</em><em>x</em><em> </em><em>→</em><em> </em><em>2</em><em>×</em><em>5</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em>

<em>Hence</em><em>,</em><em> </em><em>value</em><em> </em><em>of </em><em>JK </em><em>is </em><em>1</em><em>0</em><em>.</em>

<em>hope </em><em>this </em><em>answers</em><em> </em><em>helps</em><em> you</em><em> </em><em>dear.</em><em>.</em><em>.</em><em>take </em><em>care </em><em>and </em><em>may</em><em> u</em><em> have</em><em> a</em><em> great</em><em> day</em><em> ahead</em><em>!</em>

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. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight (in poun
tatiyna

Answer:

Step-by-step explanation:

From the problem we know that 12% of Lisa's original weight is 21 pounds. Let's call Lisa's original weight x and rewrite what we know from the question in terms of x.

We can convert 12% into a decimal - 0.12. We can also recognize that the word "of" used in a word problem often means you need to multiply. So, we can multiply 0.12 by x because we know 12% of Lisa's original weight.

0.12x = 21

To solve this equation, we need to isolate x, so we can divide both sides by 0.12.

x = 175. ==> Lisa's original weight was 175 pounds.

If you don't have a calculator or would like to learn another way to solve this problem, you can use proportions.

We know that 12% of x is 12, so what is 100% of x? (this is another way to rewrite the question)

We can contine to rewrite this by writing

\frac{12}{21} = \frac{100}{x}

We can write this because we know that the ration of 12% to 21 pounds is going to be the same ratio of 100% to Lisa's entire body weight.

We can multiple by both sides of the equation by  \frac{21x}{21x}, which is equal to 1 so it won't change the value of the equation, to remove the denominators. Then, we'll end up with:

12x = 100*21

12x = 2100

x = 175

3 0
4 years ago
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