The correct answer is 6*10^-6 ..........................
The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:
(X-h)^2 + (y-k)^2 = r^2
As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9
Substituting these values into the standard form of the equation of a circle given above:
(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81
The standard form is x^2 + y^2 =81
I’m pretty sure this is right
Answer:
3, - 2, - 7, - 12, - 17, - 22
Step-by-step explanation:
To find the first 6 terms substitute n = 1, 2, 3, 4, 5 into the formula, that is
t(1 + 1) = t(1) - 5 ⇒ t(2) = 3 - 5 = - 2
t(2 + 1) = t(2) - 5 ⇒ t(3) = - 2 - 5 = - 7
t(3 + 1) = t(3) - 5 ⇒ t(4) = - 7 - 5 = - 12
t(4 + 1) = t(4) - 5 ⇒ t(5) = - 12 - 5 = - 17
t(5 + 1) = t(5) - 5 ⇒ t(6) = - 17 - 5 = - 22
Answer:
a. 1 263 888
b. 130 701
c. 72 years
Step-by-step explanation:
a. The differential equation applies here.
Let the quantity increase for a certain time be given by Q(t)
Every unity of time, the quantity increases by 
so that after the time t, the quantity remaining will be given by:
In a similar manner, the quantity R(t) decreases at a rate given by the following expression:
and after the time , t the quantity of R remaining will be given by:
a. To find the population of humans in 1953
1993 - 1953 = 40 years = t
Q(40) = Q×
Q = 1 263 888.44
≈ 1 263 888
b. For bear population in 1993:
t = 40
R(40) = 
b = 130 700. 889
≈130 701
c. time taken for black bear population number less than 100 is given by:
130 = 11000×
solving using natural logarithms gives t = 72.72666
= 72 years Ans
