1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex_Xolod [135]
3 years ago
9

(x-2)(x+8)=0 Solve for x

Mathematics
2 answers:
sesenic [268]3 years ago
8 0
X - 2 = 0
x + 8 = 0

1. Add 2 to both sides to isolate x.
2. Subtract 8 to both sides to isolate x.

x = 2
x = -8
Lapatulllka [165]3 years ago
5 0
X - 2 = 0
X + 8 = 0

X= 2
X= -8
You might be interested in
In a geometry class, the students were asked to prove the theorem below by contradiction.
Readme [11.4K]
<span>The contradiction term for "at most one obtuse angle" is "no obtuse angles
so therefore i conclude that the </span> statement she will  most likely use as an assumption is
  Let each angle of a triangle be acute
so option A is correct
hope it helps
4 0
3 years ago
What is the ratio of 120%
Helga [31]

Answer:

5: 6

Step-by-step explanation:

becuase it was basically 100:120 but divide it by 20 and thats  how you get 5;6

7 0
3 years ago
What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)
Pachacha [2.7K]

Answer:

The third option listed: \sqrt[3]{2x} -6\sqrt[3]{x}\\

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

7\sqrt[3]{2x}  -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x}  -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x}  -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}

Therefore this is the simplified radical expression: \sqrt[3]{2x} -6\sqrt[3]{x}\\

5 0
3 years ago
What is t²=81. thanks!!
seraphim [82]

Answer:

t= 9, t= -9

Step-by-step explanation:

6 0
3 years ago
Simplify (1 − cos x)(1 + cos x). (2 points)
Vadim26 [7]

Answer:

sin²x

Step-by-step explanation:

we have

(1 − cos x)(1 + cos x)=1-cos²x

Remember that

sin²x+cos²x=1 ------> i-cos²x=sin²x

therefore

(1 − cos x)(1 + cos x)=sin²x

4 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the binomials below is a factor of this trinomial? x2 - x-12 A) x+6 B) x+4 C) x-4 D) x-6
    5·1 answer
  • What is the product of
    12·1 answer
  • Which statements are true regarding the the price of the arrangements select three answers.
    6·1 answer
  • A small theater had 8 rows of 23 chairs each. Workers just removed 6 of these chairs. How many chairs are left?
    13·1 answer
  • Find the quanity 103% of 19
    6·2 answers
  • HELP ME PLZZ I NEED HELP WITH THIS
    10·1 answer
  • If a triangle has three unequal sides, what is true about the angles of the triangle?
    10·1 answer
  • How are y'all doing today?
    13·2 answers
  • Solve. 213−12x=−23 Enter your answer in the box.
    11·1 answer
  • If f(x)=x^2+2x-10 what is f(-2)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!