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Anon25 [30]
2 years ago
11

Two less than seven times a number cbtw this is write the phrase as an algebraic expression​

Mathematics
1 answer:
velikii [3]2 years ago
8 0

Answer:

3c-2

Step-by-step explanation:

Hope it helps!!!!!!!

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What is the product?<br> (-2x- 9y2 )(-4x-3)
lara [203]

Answer:

36xy^2 + 8x^2 + 27y^2 + 6x

Step-by-step explanation:

Use the FOIL method of multiplying binomials.

First term in each binomial: -2x * -4x = 8x^2

Outside terms: -2x * -3 = 6x

Inside terms: -9y^2 * -4x = 36xy^2

Last term in each binomial: -9y^2 * -3 = 27y^2

Now, rearrange the terms correctly. 36xy^2 + 8x^2 + 27y^2 + 6x

This is our final answer, since it can not be simplified any more.

4 0
3 years ago
2)
Ira Lisetskai [31]

answer = ) 100.80

Step-by-step explanation:

I subtracted the people who payed on the 1st of the month which was 4 from the total 12 memebers. I got 8, then that 8 payed on the 2nd of the month so I multiplied 8 by 12.60

5 0
2 years ago
37% dextrose solution (37 mg per 100ml of solution) is given iv. Suppose a total of 3.81 liters is given over a 15 hour period.
sashaice [31]

Answer:

During 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be 93.98 mg/hour.

Step-by-step explanation:

If a total of 3.81 liters of the solution is given over a 15 hour period.

Now, 1 liter is equivalent to 1000 ml

So, a total of 3810 ml of the solution is given over a 15 hour period.

If 100 ml of solution contains 37 mg of dextrose, then 3810 ml of the solution will contain \frac{37 \times 3810}{100} = 1409.7 mg of dextrose.

So, during the 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be \frac{1409.7}{15} = 93.98 mg/hour. (Answer)

7 0
3 years ago
I need help with these! Thanks!!
spin [16.1K]
-2[9 - (x + 7)]
-2[9 - x - 7]
-2[-x + 9 - 7]
-2[-x + 2]
-2[-x] - 2[2]
2x - 4

The answer is C.
8 0
3 years ago
(will mark as brainliest)
Helga [31]

Find the x and y-intercepts of the equation. Then calculate the points at constant intervals and plot and connect those points on a makeshift graph. A quadratic equation can have 2 solutions, 1 solution, or none. The corresponding graphs(if two solutions) would most probably cross over the x-axis twice.

Hope this helps.

4 0
2 years ago
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