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tatiyna
4 years ago
7

A store receives shipments of peaches and wants to sort them by weight.

Mathematics
1 answer:
elena-s [515]4 years ago
6 0

Answer:

The sorting pattern is as follows:

Apples: Pound = 4:1 or 1.75:1 or 1:1.75

Given are i) 15 apples to 26.25 lbs = 15:26.25=1:1.75 Hence goes to the third box

ii) 14 apples to 3.5 lbs =14:3.5 = 4:1 lb. hence, goes to first box

iii) 2 apples to 0.5 lbs: =2:0.5 =4:1   hence, goes to first box

iv) 20 apple to 35.0 lbs: =20:35.0 =1:1.75   hence, goes to third box

v) 7 apples to 4.0 lbs: = 7:4.0=1.75:1   hence, goes to second box

i    - Third box

ii   -  First box

iii   - First box

iv) -   third box

v) - second box

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Georgia [21]

Answer:

As x → -∞, f(x) → 0.5; as x → ∞, f(x) → 0.5

Step-by-step explanation:

Given function:

f(x)=\dfrac{4x-7}{8x+8}

<u>Asymptote</u>: a line that the curve gets infinitely close to, but never touches.

As the degrees of the numerator and denominator of the given function are equal, there is a horizontal asymptote at  y=\dfrac{a}{b}  (where a is the leading coefficient of the numerator, and b is the leading coefficient of the denominator).  This is the end behavior.

\textsf{Horizontal asymptote}:y=\dfrac{4}{8}=\dfrac{1}{2}

This is because as x \rightarrow \infty the -7 of the numerator and the +8 of the denominator become negligible.  Therefore, we are left with:

f(x) \rightarrow \dfrac{4x}{8x}

Therefore:

\textsf{As }\:x \rightarrow - \infty, f(x) \rightarrow 0.5

\textsf{As }\:x \rightarrow \infty, f(x) \rightarrow 0.5

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2 years ago
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Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















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Any of the three can line up first; either of the remaining two can line up second, and the remaining person can line up last. Thus there are 3×2×1 possible orders.

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Answer:

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