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inessss [21]
2 years ago
9

Find the slope intercept form of the equation of the line that’s has the given properties (1 , 3) m=1/4

Mathematics
1 answer:
Helga [31]2 years ago
4 0

Answer:

y = 1/4x + 11/4

Step-by-step explanation:

Given the slope, m = 1/4, and the point, (1, 3):

We can substitute these values into the slope-intercept form, y = mx + b, in order to solve for the y-intercept.  

The y-coordinate (b) of the point, (0, <em>b </em>) is the <u>y-intercept </u>of the line where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0.

y = mx + b

3 = 1/4(1) + b

3 = 1/4 + b

Subtract 1/4 from both sides:

3 - 1/4 = 1/4 - 1/4 + b

11/4 = b

The y-coordinate, b, of the y-intercept is 11/4.

Therefore, the slope-intercept form is: y = 1/4x + 11/4

Please mark my answers as the Brainliest if you find this explanation helpful :)

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Work must be shown for this problem! The figure shown below is a rectangle. Make sure to solve for x and BD. Give both answers b
Mila [183]

Answer:

x = 10

BD = 74

Step-by-step explanation:

Find x by setting 3x+7 equal to 37. Solve for x by subtracting 7 on both sides then divide by 3 to get x=10.

Since 37 is half of AC, multiply that by 2 to find AC or BD, which are the exact same length of 74.

7 0
3 years ago
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Select all of the transformations that could change the location of the asymptotes of a cosecant of secant function.
mars1129 [50]

We have to select all of the transformations that could change the location of the asymptotes of a cosecant of secant function.

So given function can be written as:

y=csc( sec(x))

First we need to determine the location of asymptote which is basically a line that seems to be touching the graph of function at infinity.

From attached graph we see that Asymptotes (Green lines) are vertical.

So Vertical shift or vertical stretch will not affect the location of asymptote because moving up or down the vertical line will not change the position of any vertical line.

only Left or right side movement will change the position of vertical asymptote. Which is possible in Phase shift and period change.

Hence Phase shift and Period change are the correct choices.


8 0
3 years ago
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13.5 is 15% of what number?<br> O A) 111.1<br> OB) 60<br> OC) 202.5<br> OD) 90
Nostrana [21]

Answer: 90

Step-by-step explanation:

15% of 90 = 13.5

4 0
2 years ago
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A sorority has 38 members, 28 of whom are full members and 10 are pledges. Two persons are selected at random from the membershi
butalik [34]

Answer:

(a) 185/703

(b) 518/703

(c) 45/703

(d) 140/703

(e) 140/703

(f) 378/703

(g) 185/703

Step-by-step explanation:

Let the event of pledge member be P and event of full member be F

(a)If the first is a pledge, then the second is either a pledge or a member.

required Probabability = [P n (PUF)]

= Pr(PnP) U Pr (PnF)

= 10/38 × 9/37 + 10/38 × 28/38

= 90/1406 + 289/1406 = 370/1406

= 185/703

(b) if the person selected is not a pledge then the person is a full member and the second is either a full member or pledge

The required probability = Fn(FUP) =Pr (FnP) U Pr(FnF)

= 28/38 × 10/37 + 28/38 × 27/37

= 280/1406 + 756/140 = 1036/1406

= 518/703

(c) probability required= Pr(P/P) = Pr(PnP) = 10/38 × 9/37

= 90/1406

= 45/703

(d) Probability required = Pr(F/P)

= Pr(P) nPr(F) = 10/38 × 28/37

= 280/1406

= 140/703

(e) Probability required = Pr(P/F)

= Pr(F) n Pr(P)

= 28/38 × 10/37 =280/1406

=140/704

(f) Probability required = Pr (FnF)

= Pr(F) n Pr(F)

= 28/38 × 27/37= 756/1406

= 378/703

(g) it is the either the first person is a pledge member or a full member

Probability required = Pr[(PnP) U (FnP)]

= Pr(PnP) + Pr(FnP)

= 10/38 × 9/37 + 28/38 × 10/37

= 90/1406 + 280/1406

= 370/1406

= 185/703

(h) see attachment.

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storchak [24]

Answer:

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Step-by-step explanation:

iwdyhbjksgcsbhhsnnsgdhhsns

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