The table shows the lowest temperatures recorded on five days in April 2020, but the value for 4/23/20 has been lost . if X Is t
he lost value , and we know that X was the middle value of the five days , which choice could be the value of X?
A. -1.9 °C
B. -0.9 °C
C. -0.1 °C
D. -0.4 °C
A. -1.9 °C
B. -0.9 °C
C. -0.1 °C
D. -0.4 °C
2 answers:
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Answer:
<em>The distance from the point to the line is approximately 3.2 units</em>
Step-by-step explanation:
<u>Distance From a Point to a Line</u>
Is the shortest distance from a given point to any point on an infinite straight line. The shortest distance occurs when the segment from the point and the line are perpendiculars.
If the line is given by the equation ax + by + c = 0, where a, b and c are real constants, the distance from the line to a point (x0,y0) is
The line is given by the equation:
y=3x. We need to transform it into the specified form.
Subtracting 3x:
y - 3x = 0
Comparing with the general form of the line, we have
a=-3, b=1, c=0
The point (xo,yo) is (-1,7), thus:
The distance from the point to the line is approximately 3.2 units
Answer:
21.63 m
Step-by-step explanation:
Given :
Hypotenus = 42 m
Base = 36 m
Hence, using Pythagoras rule :
Opposite = √hypotenus² - Adjacent²
Height = √42²-36²
Height = √1764 - 1296
Height = √468
= 21.63 m
I 4 - v I < 5
I f(v) <span>I < a
</span>
f(v) < a and f(v) > - a
4 - v < 5 and 4 - v > -5
4 - v < 5
v > 4 - 5
v > - 1
4 - v > -5
v < 5 + 4
<span>v < 9
</span>
Combine the rangers
-1 < v < 9
image attached
hope this helps!
I f(v) <span>I < a
</span>
f(v) < a and f(v) > - a
4 - v < 5 and 4 - v > -5
4 - v < 5
v > 4 - 5
v > - 1
4 - v > -5
v < 5 + 4
<span>v < 9
</span>
Combine the rangers
-1 < v < 9
image attached
hope this helps!