Answer:
the company must buy 22 gallons to paint this entire area
Step-by-step explanation:
The circumference of the tank is given and is C = 2(pi)r, where r is the area.
118 ft
Here the circumference is C = 2(pi)(r) = 118 ft, which leads to r = ------------ ≈
18.79 ft ≈ r 2(pi)
The area of the sides is A = (circumference)(height), or approximately
(118 ft)(50 ft) = 5900 ft², and the area of the top is A = πr², which here comes to (π)(18.79 ft)² ≈ 1109 ft². Combining these two sub-areas, we get:
A(total) = 1109 ft² + 5900 ft² ≈ 7009 ft²
To determine how many gallons of paint will be needed to paint only the top and sides, we divide 7009 ft² by the coverage rate, which is
320 ft²
-----------
1 gallon
which results in:
7009 ft²
---------------------- ≈ 21.9 gallons
320 ft² / gallon
Since the paint comes only in full gallon cans, the company must buy 22 gallons to paint this entire area.
Answer:
40. make sure to follow me
Answer:
X-int.: (4,0)
Y-int.: (0,2)
Step-by-step explanation:
6/7 already reduced to the lowest terms;
the numerator and the denominator have no common prime factors:
6 = 2 × 3;
7 is a prime number;
98/100 = (2 × 72)/(22 × 52) = ((2 × 72) ÷ 2)/((22 × 52) ÷ 2) = 49/50;
Answer:
15
x
+
10
y
Factor
5
out of
15
x
.
5
(
3
x
)
+
10
y
Factor
5
out of
10
y
.
5
(
3
x
)
+
5
(
2
y
)
Factor
5
out of
5
(
3
x
)
+
5
(
2
y
)
.
5
(
3
x
+
2
y
)
Step-by-step explanation:
