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Ainat [17]
3 years ago
11

Ormond Oil company wants to paint one of its cylindrical

Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

the company must buy 22 gallons to paint this entire area

Step-by-step explanation:

The circumference of the tank is given and is C = 2(pi)r, where r is the area.                                                                              

                                                                                                             118 ft

Here the circumference is C = 2(pi)(r) = 118 ft, which   leads to r = ------------ ≈

18.79 ft ≈ r                                                                                                     2(pi)

The area of the sides is A = (circumference)(height), or approximately

(118 ft)(50 ft) = 5900 ft², and the area of the top is A = πr², which here comes to (π)(18.79 ft)² ≈ 1109 ft².  Combining these two sub-areas, we get:

A(total) = 1109 ft² + 5900 ft² ≈ 7009 ft²

To determine how many gallons of paint will be needed to paint only the top and sides, we divide 7009 ft² by the coverage rate, which is

320 ft²

-----------

1 gallon

which results in:

7009 ft²

----------------------  ≈  21.9 gallons

320 ft² / gallon                          

Since the paint comes only in full gallon cans, the company must buy 22 gallons to paint this entire area.                                                        

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