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Alex777 [14]
2 years ago
14

5. Marie buys 2 pounds of turkey and 1 pounds of ham. She pays a total of $20,

Mathematics
1 answer:
NARA [144]2 years ago
8 0

Answer:Let t = cost per pound of turkey

Let h = cost per pound of ham

 

4t + 2h = 30

t = h - 1.5

 

substitute h-1.5 in place of t in 1st equation

 

4(h-1.5) + 2h = 30

4h - 6 + 2h = 30

6h - 6 = 30

6h = 36

h = 6

 

t = h-1.5 = 4.5

 

1 pound of turkey costs $4.50

1 pound of ham costs    $6.00

                                ----------

cost of 1 pound each  $10.50

Step-by-step explanation:

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Answer:

a) P(x<5)=0.

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Step-by-step explanation:

We have the function:

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P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

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P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

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Therefore, the probability is P=0.216.

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P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1

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