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2 years ago

8 km 6 km What is the length of the hypotenuse? kilometers C

Mathematics

1 answer:

hammer [34]2 years ago

3 0

Answer:

Step-by-step explanation:

We use pythagorean theorem:

a^2 + b^2 = c^2

8^2 + 6^2 = c^2

$\sqrt{36 + 64} = \sqrt{100} = 10$

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How mathematics is involved in Merchandising?

Nookie1986 [14]

Answer:

You have to have the number of items you payed for and know what numbers your calculating at checkout

Step-by-step explanation:

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3 years ago

Whats the definition of a circle?

Katarina [22]

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3 years ago

Read 2 more answers

3,969 + b^2 = 11,025

ludmilkaskok [199]

Answer:

b=84

Step-by-step explanation:

from your equation, subtract 3969 from each side

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3 years ago

Read 2 more answers

How to differentiate ?

Bas_tet [7]

Use the power, product, and chain rules:

$y = x^2 (3x-1)^3$

• product rule

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}$

• power rule for the first term, and power/chain rules for the second term:

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}$

• power rule

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3$

Now simplify.

$\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}$

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

$\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) = \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)$

Differentiate both sides and you end up with the same derivative:

$\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2$

7 0

2 years ago

Joslyn wants to buy 4 packs of pens for $12.00 each and a pack of pencils for &6.00. How much money does she need

seropon [69]

$54 is your answer

You multiply $12.00 by 4 packs of pens and then add $6.00 for the pencils.

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3 years ago