If today is august 4th,2010, and your company uses LIFO, inventory purchased on which of these dates should be sold first?

one possible combination is red and hearts. write down all the other possible combinationas. write your answer like this (R,H) y

NeX [460]

Answer:

hmmmm.... sorry but i really dont know this yet

Step-by-step explanation:

4 0

2 years ago

The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.

ololo11 [35]

Answer: (a) {a, ar, ar², ar³, ar⁴, ar⁵...}, (b) arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0

3 years ago

5k - 4p + 3k +2p<br>Please show working

xeze [42]

Answer:

here

5k - 4p + 3k + 2p

=5k + 3k - 4p + 2p

=8k - 2p ans.

7 0

3 years ago

Read 2 more answers

For the quadratic relation y = -3x2 - 7x + 8,

Varvara68 [4.7K]

Answer:

a) y-int is at (0, 8)

b) zeros are at (0.8, 0) and (-3.2, 0); after having rounded to the nearest tenth.

Step-by-step explanation:

Given that y = -3x² - 7x + 8

we can find our y-intercept by setting x = 0

y = -3 (0)² - 7 (0) + 8

y = 8

so, our y intercept is at (8, 0)

To find our zeros, or x-intercepts, we need to set y = 0

0 = -3x² - 7x + 8

Let's use the quadratic formula

x = (-b ± √(b² - 4 (a * c))) / 2a

where, in this case

a = -3

b = -7

c = 8

x = (7 ± √((-7)² - 4 (-3 * 8))) / (2 * -3)

x = (7 ± √(49 - -96) / -6

x = (7 ± √145) / -6

using the addition pathway

x = (7 + √145) / -6

x = 3.2

using the subtraction pathway

x = (7 - √145) / -6

x = -0.8

So, our x-intercepts, or zeros, will lie on the points

(0.8, 0) and (-3.2, 0)

Create a table of x and y values using the given equation, and plot and graph. Clearly label your y and x intercepts.

(x, y)

(-3, 2)

(-2, 10)

(-1, 12)

(0, 8)

(1, -2)

(2, -18)

(3, -40)

4 0

3 years ago

Read 2 more answers

Yea I can do tomorrow it would take me to get the money back to you

Tems11 [23]

Given, the equation that represents the height of an object:

$y(t)=100t-16t^2$

First, we will find the velocity of the object which is the first derivative of the height using the method of the limits

$\frac{dy}{dt}=\lim_{h\to a}\frac{y(3+h)-y(3)}{(3+h)-(3)}$

We will find the value of the function y(t) when t = 3, and when t = 3+h

$\begin{gathered} y(3+h)=100(3+h)-16(3+h)^2 \\ y(3+h)=300+300h-16(9+6h+h^2) \\ y(3+h)=300+300h-144-96h-16h^2 \\ y(3+h)=156+4h-16h^2 \\ y(3)=100(3)-16(3)^2=156 \end{gathered}$

Substitute y(3+h) and y(3) into the expression of the limit

$\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}\frac{156+4h-16h^2-156}{3+h-3}=\lim_{h\to a}\frac{4h-16h^2}{h} \\ \\ \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \end{gathered}$

Where a = 0

d) compute the instantaneous velocity at t = 3

$\frac{dy}{dt}|_{t=3}=100-16*2*3=4$

So, the answer will be:

$\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \\ a=0 \\ \\ \frac{dy}{dt}|_{t=3}=4\text{ ft/sec} \end{gathered}$

5 0

1 year ago