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Archy [21]
3 years ago
5

Solve the problems.

Mathematics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

I believe a is -14

Step-by-step explanation:

its -14 because if it is in the exact same spot below water, think of the water as point 0. the bird is 14 and the fish is -14. Hope this helped

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Four less than the quotient of a number x and 5
pochemuha
The equation is
x/5-4
4 0
4 years ago
Read 2 more answers
-4(1.75+1x)=18 What does x equal
77julia77 [94]

Answer:

x = -6.25

Step-by-step explanation:

-4(1.75 + 1x) = 18

1.75 + 1x = 18/-4

1.75 - 1.75 + x = -4.5 - 1.75

x = -6.25

Answer:  x = -6.25

8 0
4 years ago
What is the surface area of this rectangular prism?
Sloan [31]
Hello!

First of all, let's find the area of the bases. We can see that the base is 8 by 6, or 48. We have this onto the top as well. This gives us 96. We can multiply The area of each side (base,front, side) by two to get the other side. Then we will add.

48(2)=96 (Base)
42(2)=84 (Side)
56(2)=112 (Front)

Now we add all of our numbers up.

96+84+112=292

Therefore, our answer is B) 292 in²

I hope this helps!

6 0
3 years ago
Find the value of this expression if x = 3.<br> x2 + 3<br> x-1
andre [41]

Answer:

1. 9

2. 2

Step-by-step explanation: First you would plug in the number for the variable then add or subtract. Instead of x2 + 3, it would be 3* 2 + 3 which is 9

6 0
3 years ago
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A circle has its center at the center of a square with 26-inch sides. Using 3.14 for pi, find the area of the square not covered
AlladinOne [14]
For squrae
area=side²
perimiter=4(side)

for circle
area=pir²
circumference=2pir

side=diameter, diameter/2=radius=side/2


find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches

areanotcovered=676-530.66=145.34 square inches not coverd


ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785

7 0
3 years ago
Read 2 more answers
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