A circle has its center at the center of a square with 26-inch sides. Using 3.14 for pi, find the area of the square not covered by the circle, then write a ratio of the circle’s circumference to the perimeter of the square.
2 answers:
For squrae area=side² perimiter=4(side) for circle area=pir² circumference=2pir side=diameter, diameter/2=radius=side/2 find area not covered that is areasquare-areacircle areasquare=26²=676 sqauare inches areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches areanotcovered=676-530.66=145.34 square inches not coverd ratio of perimiter to circumferece perimiter=4*26=104 circumference=2pir=2pi13=26pi=26*3.14=81.64 circumference to perimiter is 81.64/104=0.785
area of square = s^2 = (26)^2
area of circle = pi*r^2 = 3.14*(13)^2
area of square not covered by the circle = 26^2-3.14(13)^2
perimeter of square = 4s = 4(26) = 104
circumference of circle = pi*d = 3.14*26
circumference:perimeter ratio => 3.14:4
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