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Fudgin [204]
3 years ago
8

Please help me to answer this question​

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0
Where’s the question
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Stuck, anyone can help?
expeople1 [14]

Answer:

Step-by-step explanation:

\sqrt{x-3} = x - 5 ( x ≥ 3 )

( \sqrt{x-3} )² = ( x - 5 )²

x - 3 = x² - 10x + 25

x² - 11x + 28 = 0

(x - 4)(x - 7) = 0

x_{1} = 7

x_{2} = 4

Check the answer:

1). x = 7

\sqrt{7-3} = 7 - 2

√4 = 2

2 = 2

2). x = 4

\sqrt{4-3} = 4 - 5

1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.

6 0
2 years ago
I can't figure out how to do <br> -5+x/3=-11
-BARSIC- [3]
Add 5 to both sides
5-5+x/3=5-11
0+x/3=-6
x/3=-6
times both sides by 3
3x/3=-18
x=-18
3 0
3 years ago
A bakery uses a muffin recipe that uses 1/2 cup of milk for every batch of 12 muffins.... How many batches of 12 muffins can be
Irina-Kira [14]
32 batches of 12 muffins hope this helps
6 0
3 years ago
ILL GIVE BRAINLIEST PLS HELP ME
luda_lava [24]

One solution

The two (or more) equations would only intersect once

No solution

Lines never intersect

The lines are parallel

Infinite solutions

The lines are the exact same

That’s all the characteristics I know

3 0
3 years ago
Vertex of x^2-10x+30
Shtirlitz [24]

The easiest way to find the vertex is to convert this standard form equation into vertex form, which is y = a(x - h)^2 + k.

Firstly, put x^2 - 10x into parentheses: y = (x^2 - 10x) + 30

Next, we want to make what's inside the parentheses a perfect square. To do that, we need to divide the x coefficient by 2 and square it. In this case, the result is 25. Add 25 inside the parentheses and subtract 25 outside of the parentheses: y = (x^2 - 10x + 25) + 30 - 25

Next, factor what's inside the parentheses and combine like terms outside of the parentheses, and your vertex form is: y = (x - 5)^2 + 5.

Now going back to the formula of the vertex form, y = a(x - h)^2 + k, the vertex is (h,k). Using our vertex equation, we can see that the vertex is (5,5).

3 0
3 years ago
Read 2 more answers
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