Answer:
Option A is correct.
The given expression : 
then;
Step-by-step explanation:
Given the expression:
Cross multiplication the given expression following steps are as follow;
- Multiply numerator of the left-hand fraction by the denominator of the right-hand fraction
- Also, Multiply numerator of the right-hand fraction by the denominator of the left-hand fraction.
- then, set the two products equal to each other.
Using cross multiplication, on the given expression;
First multiply the numerator of the left hand fraction(i.e,a ) by the denominator of the right hand fraction (i,e a)
we have;
Simplify:
[1]
now, multiply numerator of the right-hand fraction( i.e, 9) by the denominator of the left-hand fraction (i.e, 4 ) in [1]
we have;
Simplify:
Therefore, the given expression is equal to:
36 = 1/2 (AE - 26)
72 = AE - 26
98 = AE
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
Answer:
The correct option is D
D) She may not be correct because means cannot be determined from the box plots
Step-by-step explanation:
The question is incomplete because the box plots are not attached in the question. I've attached the box plots of this question at the bottom.
The box plot, also know as box and whisker plot, displays only five type of values, which are:
- Minimum value
- First Quartile
- Median
- Third Quartile
- Maximum value
Mean cannot be determined by just lookin at the box plots. To find the mean, we need to know the values of data and total number of values.
As mean cannot be determined from the box plot, correct option is D
Problem
evaluate the function
f(-x) = f(x)
plug in the points (2,1) then solve
Solution
For this case we can conclude that:
f(2) =1
So then we satisfy that:
f(-2) =1
