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3 years ago

Help this is hard for me, please..I give brainliest also this is 20 points

Mathematics

1 answer:

bazaltina [42]3 years ago

6 0

Answer:

-14 Mexican pesos means you have a debt of $0.67 at today's exchange rates.

Step-by-step explanation:

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2<br> Select the correct answer.<br> Simplify the following expression.

sp2606 [1]

Answer:

The answered would be 1/64 since it's simplified

5 0

3 years ago

Read 2 more answers

Which is the distance between points (0,3) to (5,-9) on the coordinate plane?

pogonyaev

This would be:-

square root [ (5-0)^2 + (-9 -3)^2) ]

= square root ( 25 + 144)

= sqrt 169

= 13 Answer

4 0

4 years ago

Read 2 more answers

Evaluate this problem look at them do it right will mark brianlist and 2o extra points

ale4655 [162]

◆ Playing with numbers ◆

Hey !!

Check the attachment.
Hope it helps you :)

6 0

3 years ago

If X is a r.v. such that E(X^n)=n! Find the m.g.f. of X,Mx(t). Also find the ch.f. of X,and from this deduce the distribution of

astraxan [27]

$M_X(t)=\mathbb E(e^{Xt})$
$M_X(t)=\mathbb E\left(1+Xt+\dfrac{t^2}{2!}X^2+\dfrac{t^3}{3!}X^3+\cdots\right)$
$M_X(t)=\mathbb E(1)+t\mathbb E(X)+\dfrac{t^2}{2!}\mathbb E(X^2)+\dfrac{t^3}{3!}\mathbb E(X^3)+\cdots$
$M_X(t)=1+t+t^2+t^3+\cdots$
$M_X(t)=\displaystyle\sum_{k\ge0}t^k=\frac1{1-t}$

provided that $|t|$ .

Similarly,

$\varphi_X(t)=\mathbb E(e^{iXt})$
$\varphi_X(t)=1+it+(it)^2+(it)^3+\cdots$
$\varphi_X(t)=(1-t^2+t^4-t^6+\cdots)+it(1-t^2+t^4-t^6+\cdots)$
$\varphi_X(t)=(1+it)(1-t^2+t^4-t^6+\cdots)$
$\varphi_X(t)=\dfrac{1+it}{1+t^2}=\dfrac1{1-it}$

You can find the CDF/PDF using any of the various inversion formulas. One way would be to compute

$F_X(x)=\displaystyle\frac12+\frac1{2\pi}\int_0^\infty\frac{e^{itx}\varphi_X(-t)-e^{-itx}\varphi_X(t)}{it}\,\mathrm dt$

The integral can be rewritten as

$\displaystyle\int_0^\infty\frac{2i\sin(tx)-2it\cos(tx)}{it(1+t^2)}\,\mathrm dt$

so that

$F_X(x)=\displaystyle\frac12+\frac1{2\pi}\int_0^\infty\frac{\sin(tx)-t\cos(tx)}{t(1+t^2)}\,\mathrm dt$

There are lots of ways to compute this integral. For instance, you can take the Laplace transform with respect to $x$ , which gives

$\displaystyle\mathcal L_s\left\{\int_0^\infty\frac{\sin(tx)-t\cos(tx)}{t(1+t^2)}\,\mathrm dt\right\}=\int_0^\infty\frac{1-s}{(1+t^2)(s^2+t^2)}\,\mathrm dt$
$=\displaystyle\frac{\pi(1-s)}{2s(1+s)}$

and taking the inverse transform returns

$F_X(x)=\dfrac12+\dfrac1\pi\left(\dfrac\pi2-\pi e^{-x}\right)=1-e^{-x}$

which describes an exponential distribution with parameter $\lambda=1$ .

6 0

3 years ago

A triangular flag has an area of 22 cm². Jon measures the height as 8 cm, what is the base length?

dedylja [7]

The base length is 5.5 cm.

Explanation:

Area of triangle = base x height x 1/2

Let b cm be the base length of the triangular flag.

22 = b x 8 x 1/2

22 x 2 ÷ 8 = b

b = 44 ÷ 8

b = 5.5

4 0

3 years ago