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ehidna [41]
3 years ago
5

One of the most important things to practice while dribbling is using your peripheral vision.

SAT
1 answer:
Paladinen [302]3 years ago
3 0

Answer:

True!

Explanation:

I took this test in school too. The answer is true ;)

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After the torque has been applied for 0.3 s, what are the magnitude and direction of the angular momentum about the center of th
vredina [299]

The magnitude and direction of the angular momentum about the center of the disk is 0.996 kgm²/s.

<h3>Angular acceleration of the disk</h3>

The angular acceleration of the disk is determined by applying the principle of conservation of angular momentum as shown below;

Fr = Iα

α = Fr/I

Where;

  • I is the moment of inertia of the solid disk

I = ¹/₂MR²

I = ¹/₂ x (0.5) x (0.08)²

I = 1.6 x 10⁻³ kgm²

\alpha = \frac{14 \times 0.22}{1.6\times 10^{-3}}\\\\\alpha = 1,925 \ rad/s^2

<h3>Final angular velocity of the disk</h3>

ωf = ωi + αt

ωf = 45 + (1925 x 0.3)

ωf = 622.5 rad/s

<h3>Angular momentum</h3>

L = Iω

L = (1.6 x 10⁻³) x (622.5)

L = 0.996 kgm²/s

Thus, the magnitude and direction of the angular momentum about the center of the disk is 0.996 kgm²/s.

The complete question is below:

A uniform solid disk with radius 8 cm has mass 0.5 kg (moment of inertia I = (1/2)MR²). A constant force 14 N is applied as shown. At the instant shown, the amount of string that has wound off the disk is d = 22 cm, and the angular velocity of the disk is 45 radians/s into the page.

Learn more about angular momentum here: brainly.com/question/7538238

4 0
2 years ago
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