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1 year ago

Two congruent squares are shown in figures 1 and 2 below.

1 answer:

4 0

The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2. The area of the unshaded square in Figure 1 can be represented by . The combined area of the two unshaded squares in Figure 2 can be represented by . The areas of the squares in Figure 1 and Figure 2 show that .
Given :
Figure 1 and figure 2 are given.
The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2.
The area of the unshaded square in Figure 1 can be represented by .
The combined area of the two unshaded squares in Figure 2 can be represented by .
The areas of the squares in Figure 1 and Figure 2 show that .

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The base of s is the region enclosed by the parabola y = 3 − 2x2 and the x−axis. Cross-sections perpendicular to the y−axis are

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<h3>Integral Volume of a Solid</h3>

The length of each cross-section is determined by the horizontal distance (parallel to the x-axis) from one end of the parabola to the other.

Thus;

y = 3 - 2x²

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x = ±√[(3 - y)/2]

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⇒ 2√[(3 - y)/2]

The area of each cross-section is simply the square of the section's side length, so the area would be;

A = (2√[(3 - y)/2])²

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Thus, volume is;

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Read more about integral volume of solids at; brainly.com/question/14845570

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1 year ago

Ariana is accelerating her car at a rate of 4. 6 m/s2 for 10 seconds. Her starting velocity was 0 m/s. What was her final veloci

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Answer:

<h3>the answer is v=46 m/s</h3>

Explanation:

<h3>to find the final velocity we use formula from uniformly accelerated motion , equation 1, that is ; V=U+at</h3>

<h3>our given is U=0m/s</h3><h2> a=4.6m/s^2</h2><h3> t=10s</h3><h3>requaired,V=?</h3>

<h3>solution will be; V = u+at</h3>

<h3>replacing the values of each individual</h3>

<h3>V=0m/s+(4.6m/s^2)(10s)</h3><h3>V=0m/s+46m/s ;second found on the unit of acceleration canceled by the unit of time and finaly the left is m/s</h3><h3>V=46m/s</h3>

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