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3 years ago

James invested $1,475 in an account paying 6.25%

Mathematics

1 answer:

Ghella [55]3 years ago

3 0

Answer:

The rule says that to find the number of years required to double your money at a given interest rate, you just divide the interest rate into 72. For example, if you want to know how long it will take to double your money at eight percent interest, divide 8 into 72 and get 9 years.

Step-by-step explanation:

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Determine the slope of the line that contains the points A(0, 2) and B(7,3). *

IgorC [24]

<h3>Given points:-</h3>

A (0,2)
B (7,3)

We know that

${\boxed{\sf Slope_{(m)}=\dfrac {y_2-y_1}{x_2-x_1}}}$

Substitute the values

$\qquad\quad {:}\longrightarrow\tt m=\dfrac {3-2}{7-0}$

$\qquad\quad {:}\longrightarrow\tt m=\dfrac {1}{7}$

$\therefore \sf Slope\:of\:the\:line\:is\:\dfrac {1}{7}$

5 0

3 years ago

PLEEEAAAAAASE HELP! What is the answer to this question?

IrinaVladis [17]

Answer:

23 units

Step-by-step explanation:

Perimeter is the sum of side lengths

Let's find the sides first

AB = √(-2- 2)² + (-4+1)² = 5
BC = (2 - (-1)) = 3
CD = √(-1- 2)²+(5-2)² = √18 = 3√2 = 4.24
DE = √(-4 -(-1))²+(2-5)²= √18 = 3√2 = 4.24
AE = √(-4-(-2)²+(2-(-4))²=√40= 2√10 = 6.32

Perimeter is

P = 5 + 3 + 4.24 + 4.24 + 6.32 = 22.8 ≈ 23 rounded to the nearest whole number

7 0

3 years ago

Simplify the expression 6C2

iVinArrow [24]

Answer:

$^6C_2=15$

Step-by-step explanation:

Recall the formula:

$^nC_r=\frac{n!}{(n-r)!r!}$

We apply this formula to simplify $^6C_2$

This implies that:

$^6C_2=\frac{6!}{(6-2)!2!}$

$^6C_2=\frac{6!}{4!2!}$

$^6C_2=\frac{6\times5\times4!}{4!\times 2\times1}$

This simplifies to

$^6C_2=\frac{6\times5}{2\times1}$

$^6C_2=\frac{3\times5}{1\times1}=15$

8 0

3 years ago

If the ratio of the sides of two similar prisms is 3:5 and the volume of the first prism is 54, what is the volume of the second

Yuri [45]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{s^3}{s^3}=\cfrac{\textit{volume of smaller}}{\textit{volume of larger}}\implies \cfrac{3^3}{5^3}=\cfrac{54}{v}
\\\\\\
v=\cfrac{5^3\cdot 54}{3^3}$

3 0

3 years ago

Can anyone help with this problem

marta [7]

9514 1404 393

Answer:

A Kite A
he guessed

Step-by-step explanation:

For a quadrilateral in which the diagonals cross at right angles, such as a rhombus or kite, the area can be found as half the product of the diagonals.

For the purpose here, we can ignore the factor of 1/2, which is the same for both, and simply consider the products of the diagonals.

Kite A has an area proportional to (30 in)(30 in) = 900 in².

Kite B has an area proportional to (20 in)(40 in) = 800 in².

Kite A has a larger area, so will use more paper.

Only Rudy knows why he chose answer C. Perhaps he guessed, rather than doing any math.

8 0

3 years ago

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