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3 years ago

6

Is algebra.

1 answer:

Whitepunk [10]3 years ago

6 0

Answer: the answer is d

Step-by-step explanation:

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Use scientific notation to find the product of 7.13 × 10 -3 and 40.

OleMash [197]

Answer:

(7.13 × 10^-3) x 40 = 285.2 x 10^-3 = 2.9 x 10^-1

Step-by-step explanation:

I think this is the answer i hope if it right or not but aleast I try on it .

4 0

3 years ago

PLEASE HELP! I WILL MARK BRAINLIEST!!!

oksano4ka [1.4K]

Answer:

-8y+12

Step-by-step explanation:

4(-2y +3)

you can distribute the 4

4 • -2y + 4 • 3

= -8y +12

because they are not like terms, you cannot do anything further.

6 0

3 years ago

The circumference of the circle is below 25.12 centimeters which is the best estimestifor the length of the radius of the circle

kirill115 [55]

C=2pir
c=25.12
25.12=2pir
divide both sides by 2
12.56=pir
divide both sides by 3.14 since we will use pi=3.14
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7 0

4 years ago

(3+62) x (25-17) + 3*2 <br> 2 is an exponent btw

MAXImum [283]

Answer:

529

Step-by-step explanation:

5 0

4 years ago

The x- intercepts of a parabola are (0,-6) and (0,4). The parabola crosses the y- axis at -120. Lucas said that an equation for

astraxan [27]

Given:

The x- intercepts of a parabola are (0,-6) and (0,4).

The parabola crosses the y- axis at -120.

Lucas said that an equation for the parabola is $y=5x^2+10x-120$ and that the coordinates of the vertex are (-1, -125).

To find:

Whether Lucas is correct or not.

Solution:

The x- intercepts of a parabola are (0,-6) and (0,4). It means (x+6) and (x-4) are the factors of the equation of the parabola.

$y=a(x+6)(x-4)$ ...(i)

The parabola crosses the y- axis at -120. It means the equation of the parabola must be true for (0,-120).

$-120=a(0+6)(0-4)$

$-120=a(6)(-4)$

$-120=-24a$

Divide both sides by -24.

$\dfrac{-120}{-24}=a$

$5=a$

Substituting $a=5$ in (i), we get

$y=5(x+6)(x-4)$

$y=5(x^2+6x-4x-24)$

$y=5(x^2+2x-24)$

$y=5x^2+10x-120$

So, the equation of the parabola is $y=5x^2+10x-120$ .

The vertex of a parabola $f(x)=ax^2+bx+c$ is:

$Vertex=\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)$

In the equation of the parabola, $a=5,b=10,c=-120$ .

$-\dfrac{b}{2a}=-\dfrac{10}{2(5)}$

$-\dfrac{b}{2a}=-\dfrac{10}{10}$

$-\dfrac{b}{2a}=-1$

Putting $x=-1$ in the equation of the parabola, we get

$y=5(-1)^2+10(-1)-120$

$y=5-10-120$

$y=-125$

So, the vertex of the parabola is at point (-1,-125).

Therefore, Lucas is correct.

5 0

3 years ago