A plumber charges $70 per hour plus $40 dollars for the call. What does he charge for 4 hours of work
2 answers:
First, let's create an equation for this problem. ($70 × 4) + $40 Now, all you would have to do is solve it using the order of operation (PEMDAS). ($70 × 4) + $40 = $280 + $40 $280 + $40 = $320 The plumber charged $320. I hope this helps!
Use formula y=mx+b, where y equals total fees, m equals hourly cost(70), and b equals the cost of call(40). y=70(4)+40. y=280+40 y=320, so he charges $320 for 4 hours of work. hope this helps you!
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