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Sidana [21]
3 years ago
9

Can someone help me pls

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0
The value of X=28 while the value of y=28,hopefully this is right
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<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
Suppose Lin labels the books at a constant speed of s books per minute. There can be several equations written that represent th
Alla [95]

Answer:

S = \frac{b}{m}

Step-by-step explanation:

Given

Speed = s

Required

Determine the expression for s

The speed is calculated as:

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Substitute S for speed

S= \frac{Number\ of\ books}{Time}

Let the number of books be b and the time be m.

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S = \frac{b}{m}

Hence, the expression for the scenario is:

S = \frac{b}{m}

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3. 54
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Answer:

A

Step-by-step explanation:

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