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2 years ago

PLEASE HELP IF YOU CAN ASAP PLEASE THIS IS ALGEBRA

Mathematics

2 answers:

nadezda [96]2 years ago

8 0

Answer:

1. (I need the picture for this one)

2. m=2/3 / Slope = 2/3

Step-by-step explanation:

horrorfan [7]2 years ago

8 0

I can’t help you with questions 1 because there is no picture. For question two, this is how you would find the slope given a line with 2 points:

Solving Steps: Reasoning:
1.) m=(y2-y1)/(x2-x1) [Slope Formula]
2.) m=(x1=-2, y1=-1) (x2=4, y2=3) [Assign Value to ordered pairs]
3.) m=(3-(-1))/(4-(-2)) [Substitution P.O.E.]
4.) m=(3+1)/(4+2) [Negative minus negative = positive]
5.) m=4/6 [Addition]
6.) m=2/3 [Simplification]

Therefore, the slope (m) = 2/3. To find the Domain, you will need to list all the X-coordinates from your ordered pairs. To find the range, you will need to list all the Y-coordinates from your ordered pairs.
You can use these formula:
Domain={x1, x2, x3, x4, x5…}
Range={y1, y2, y3, y4, y5…}
You just have to input your values into these formulas. An ordered pair looks like this: (5, 4). The left value is the x-coordinate (5), and the right value is the y-coordinate (4).

Please mark Brainliest!!!

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3 years ago

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Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

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3 years ago

Need help please! A=?

zubka84 [21]

Answer:

m∠A ≈ 103°

Step-by-step explanation:

Enough information is shown for us to be able to use the Law of Sines to find the angle. That tells us ...

sin(A)/a = sin(C)/c

A = arcsin(a/c·sin(C)) = arcsin(26/6·sin(13°)) = arcsin(0.974788)

A = 77.1° or 102.9°

The claim is that the figure is drawn to scale, so we can assume that A is an obtuse angle:

m∠A ≈ 103°

<em>Additional comment</em>

The sum of angles A and B must be 180° -13° = 167°. Since angle A is the largest, it must be more than half this value, or more than 83.5°. That means, we must choose the obtuse angle for A, rather than the acute angle.

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2 years ago