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KengaRu [80]
3 years ago
10

Help please! I’m a bit young so it might be easy for you! Can you please tell me this and maybe I’ll understand? Giving brainlie

st!

Mathematics
1 answer:
astraxan [27]3 years ago
6 0

Answer:

2.36 miles

Step-by-step explanation:

subtraxt them from each other

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Solve for x: 3x - 24 = 81<br> A-57/3<br> B-105/3<br> C-57<br> D-105<br> Helpppp please
expeople1 [14]

Solution,solve\:for\:x,\:3x-24=81\quad :\quad x=35

Steps: 3x-24=81

\mathrm{Add\:}24\mathrm{\:to\:both\:sides}, 3x-24+24=81+24

\mathrm{Simplify}, 3x=105

\mathrm{Divide\:both\:sides\:by\:}3, \frac{3x}{3}=\frac{105}{3}

Simplify, x=35

The correct answer is <u><em>B. 105/3</em></u>

<u><em>Hope this helps!!!</em></u>

<3 - austint1414

5 0
3 years ago
6 music CDs to 8 DVDs, 18 music CDs to 24 DVDs. Determine whether the ratios are equivalent. Show your work
atroni [7]
They are indeed equivalent.
The ratios can be set up as 6/8 and 18/24.
Once simplified, both of these ratios become 3/4, and are therefore equivalent.
8 0
3 years ago
What ratio of height to width is considered most appropriate in graphing a frequency distribution?
Fiesta28 [93]
Answer:
As a rule of thumb, it is usual to define discrete data in 5 to 10 groups or bins. When graphed, the height of each group or bin defines the frequency for the group or bin.

Explanation:
When discrete data is graphed into a histogram, it defines a frequency distribution. Because information becomes lost when too many groups or bins are used, it is customary to use 5 to 10 bins.

Example:
Consider the following random data which has a sample size of 16.
x = [1, 3, 6, 2, 9, 8, 4, 5, 10,  3, 5, 4, 3, 5, 7,  5]
When fewer groups or bins are used to construct the histogram, the centralized nature of the distribution is easy to discern.
As the number of bins increases, the distribution becomes more difficult to define.



3 0
4 years ago
Can please send answers with step
lawyer [7]

Answer:

A. 14 Sq.cm

Step-by-step explanation:

The area of the circle is 56 cm Sq.

Half of it is 28 Sq.cm

If you combine the 2 triangles it will make an area of 7sq.cm

then the Curved shaded part is also 7sq.cm together of the shaded part will create a quarter of the whole figure

So

56/4 Sq.cm

= 14Sq.cm

Thank you!!

Mark me as brainliest :>>>

6 0
3 years ago
This says to multiply the special products how do I answer this problem? (x+8)(x-8)
meriva
(x + 8)(x - 8)
x(x - 8) + 8(x - 8) = 
x^2 - 8x + 8x - 64 =
x^2 - 64 <===
8 0
4 years ago
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