I am not sure about this but here goes nothing: d=2.5t+2.2 is very familiar to y=mx+b y=d m=2.5 x=t b=2.2 to find a new quasion we substitute d and t into place wich equals 1=2.5(0)+b simplification and you get b=1 so your answer is d=2.5t+1
Answer:
It would take 5.9 years to the nearest tenth of a year
Step-by-step explanation:
The formula of the compound continuously interest is A = P
, where
- A is the value of the account in t years
- P is the principal initially invested
- e is the base of a natural logarithm
- r is the rate of interest in decimal
∵ Serenity invested $2,400 in an account
∴ P = 2400
∵ The account paying an interest rate of 3.4%, compounded continuously
∴ r = 3.4% ⇒ divide it by 100 to change it to decimal
∴ r = 3.4 ÷ 100 = 0.034
∵ The value of the account reached to $2,930
∴ A = 2930
→ Substitute these values in the formula above to find t
∵ 2930 = 2400
→ Divide both sides by 2400
∴
= 
→ Insert ㏑ in both sides
∴ ㏑(
) = ㏑(
)
→ Remember ㏑(
) = n
∴ ㏑(
) = 0.034t
→ Divide both sides by 0.034 to find t
∴ 5.868637814 = t
→ Round it to the nearest tenth of a year
∴ t = 5.9 years
∴ It would take 5.9 years to the nearest tenth of a year
Answer:
1st blank: $51.00. 3rd blank: 1.1 5th blank: 24.2
2nd blank: $67.00. 4th blank: 91.30. 6th blank: -57.4
Step-by-step explanation:
Answer:
The percent of decrease can be calculated with this formula:
(Original value - New Value)/(Original Value)
In this case, the original value is 117 and the new value is 91.
So the percent of decrease is 26/117, or about 22%.
Hope this helps!
The answer is 0.5! Good luck