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KiRa [710]
2 years ago
10

Need help asap !!! Write an equation of the line below.

Mathematics
2 answers:
prohojiy [21]2 years ago
8 0

9514 1404 393

Answer:

  y = -1/3x +4

Step-by-step explanation:

The graph of the line has two points marked on it.

  (x1, y1) = (-6, 6) . . . . . left point

  (x2, y2) = (0, 4) . . . . right point, and y-intercept

The slope of the line is the ratio of the differences:

  m = (y2 -y1)/(x2 -x1)

  m = (4 -6)/(0 -(-6)) = -2/6 = -1/3

The y-intercept is the y-value where the line crosses the y-axis. Here, that y-value is 4.

In the slope-intercept form of the equation for the line, the slope is called <em>m</em>, and the y-intercept is called <em>b</em>. For this line, we have m=-1/3, b=4.

The equation is ...

  y = mx +b

  y = -1/3x +4 . . . . . the equation you're looking for

aliina [53]2 years ago
4 0

Answer: y intercept =  y=-1/3x+4, point-slope = (y-6)=-1/3(x+6)

Step-by-step explanation:

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A tree with a height of 4 ft casts a shadow 15ft long on the ground how tall is another tree that cast a shadow which is 20ft lo
wariber [46]

Height of another tree that cast a shadow which is 20ft long is 5 feet approximately

<h3><u>Solution:</u></h3>

Given that tree with a height of 4 ft casts a shadow 15ft long on the ground

Another tree that cast a shadow which is 20ft long

<em><u>To find: height of another tree</u></em>

We can solve this by setting up a ratio comparing the height of the tree to the height of the another tree and shadow of the tree to the shadow of the another tree

\frac{\text {height of tree}}{\text {length of shadow}}

Let us assume,

Height of tree = H_t = 4 feet

Length of shadow of tree = L_t = 15 feet

Height of another tree = H_a

Length of shadow of another tree = L_a = 20 feet

Set up a proportion comparing the height of each object to the length of the shadow,

\frac{\text {height of tree}}{\text {length of shadow of tree}}=\frac{\text { height of another tree }}{\text { length of shadow of another tree }}

\frac{H_{t}}{L_{t}}=\frac{H_{a}}{L_{a}}

Substituting the values we get,

\frac{4}{15} = \frac{H_a}{20}\\\\H_a = \frac{4}{15} \times 20\\\\H_a = 5.33

So the height of another tree is 5 feet approximately

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