For the answer to the question above, I think the answer is "A V<u><em>ise Guy</em></u><u><em> or Vise</em></u><u><em> Man</em></u>" is <span>what should you call a man with a clamp.
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I hope my answer helped. Have a nice day!
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The correct question is
<span>Sakura speaks 150 words per minute on average in hungarian, and 190 words per minute on average in polish. she once gave cooking instructions in hungarian, followed by cleaning instructions in polish. sakura spent 5 minutes total giving both instructions, and spoke 270 more words in polish than in hungarian. how long did sakura speak in hungarian, and how long did she speak in polish?</span>
Let
x------> total words spoken by sakura in hungarian------> 150 words /minute
y------> total words spoken by sakura in polish-----------> 190 words /minute
we know that
(x/150)+(y/190)=5--------- > equation 1
y=270 +x-------------------- > equation 2
<span>substituting 2 in 1
(x/150)+(270+x)/190=5
</span><span>multiplying all the expression by (150)*(190)
</span>190x+150*(270+x)=5*190*150
190x+40500+150x=142500
340x=102000-------------- > x=300
x=300 ------------- > total words spoken by sakura in hungarian
y=270+x=270+300=570
y=570 ----------- > total words spoken by sakura in polish
the question is <span>how long did sakura speak in hungarian, and how long did she speak in polish?
</span>
y=570 words in polish-------------------> 190 words /minute
if 190 words-----------------------------> 1 minute
570 words-------------------------- X
X=570/190=3 minutes
In polish Sakura spoke 3 minutes
x=300 words in hungarian-------------------> 150 words /minute
if 150 words-----------------------------> 1 minute
300 words-------------------------- X
X=300/150=2 minutes
In hungarian Sakura spoke 2 minutes
Answer:
6
Step-by-step explanation:
Answer:
g(x) = 4x²
Step-by-step explanation:
The function f(x) goes through the point f(1) = 1. The function g(x) has its vertex in the same place, so there is no translation involved, only scaling. The scale factor (a) can be found from ...
g(x) = a·f(x)
g(1) = 4 = a·f(1) = a·1
Then a=4, and the equation for g(x) is ...
g(x) = 4·f(x)
g(x) = 4x²
