Hello
DEF and IKL , equilateral =>
DE = 5x-12 = 3x-4
5x-3x= -4+12
2x= 8
x=4
DE = 5x-12 = 20-12 = 8
KL = 3x+24 = 10x+3
24 -3 = 10x-3x
21 = 7x
x= 21/7 = 3
KJ = 10x+3 = 30+3 = 33
Why not draw the graph of y=|x|? It has a v-shape, and the vertex is at (0,0).
The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward. The smallest value that y can have is therefore -3.
Can you now figure out the range of f(x)?
Answer:
4 because its not a scatter plot
Step-by-step explanation:
Answer:
Second option is correct. The x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5 is -2.
Step-by-step explanation:
From the given graph it is noticed that the endpoints of the line segment JK are J(-6,-2) and K(8,-9).
The formula to find x intercept.

The ratio is 2:5, therefore the value of m is 2 and the value of n is 5.




Therefore the x-coordinate is -2 and second option is correct.