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masya89 [10]
3 years ago
5

A sporting goods stores sells footballs, basketballs, and volleyballs. A football costs $35, a basketball costs

Mathematics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

The number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

Step-by-step explanation:

Consider the provided information.

A football costs $35, a basketball costs $25  and a volleyball costs $15.

Let F represents the football, B represents the basketball and V represents the volleyball.

On a given day, the store sold 5 times as many footballs as volleyballs.

F=5V......(1)

They  brought in a total of $3750 that day,

35F+25B+15V=3750......(2)

The money made from basketballs alone was 4 times the money.

25B=4(15V)......(3)

By equation 1, 2 and 3.

35(5V)+4(15V)+15V=3750

250V=3750

V=15

Substitute the value of V in equation 1 and 3.

F=5(15)=75

25B=4(15\times 15)\\B=36

Hence, the number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

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Step-by-step explanation:

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Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

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y = -15/(-3) ... divide both sides by -3

y = 5

-----------

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y = 5

\sqrt[5]{x^3} = 5

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x^3 = 3125

x = \sqrt[3]{3125} Apply cube root to both sides

x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

x = 5*\sqrt[3]{25}

x \approx 14.62009

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