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masya89 [10]
3 years ago
5

A sporting goods stores sells footballs, basketballs, and volleyballs. A football costs $35, a basketball costs

Mathematics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

The number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

Step-by-step explanation:

Consider the provided information.

A football costs $35, a basketball costs $25  and a volleyball costs $15.

Let F represents the football, B represents the basketball and V represents the volleyball.

On a given day, the store sold 5 times as many footballs as volleyballs.

F=5V......(1)

They  brought in a total of $3750 that day,

35F+25B+15V=3750......(2)

The money made from basketballs alone was 4 times the money.

25B=4(15V)......(3)

By equation 1, 2 and 3.

35(5V)+4(15V)+15V=3750

250V=3750

V=15

Substitute the value of V in equation 1 and 3.

F=5(15)=75

25B=4(15\times 15)\\B=36

Hence, the number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

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Suppose an opaque jar contains 3 red marbles and 10 green marbles. The following exercise refers to the experiment of picking tw
kow [346]

Answer:

\frac{5}{13}

Step-by-step explanation:

Given,

Red marbles = 3,

Green marbles = 10,

So, the total marbles = 3 + 10 = 13,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Since, here replacement is not allowed,

Thus, the probability of getting a green marble and a red marble

= first red and second green + first green second red

=\frac{3}{13}\times \frac{10}{12}+\frac{10}{13}\times \frac{3}{12}

=2\times \frac{3}{13}\times \frac{10}{12}

=\frac{30}{78}

=\frac{5}{13}

Note : The probability of getting a green marble first and a red marble second

= \frac{10}{13}\times \frac{3}{12}

=\frac{30}{156}

=\frac{5}{26}

4 0
4 years ago
Use the Distributive Property to solve the equation.
Arada [10]

Answer:

x= - 9

Step-by-step explanation:

  1. - 8(x +7) = 16
  2. -8x - 56 = 16
  3. -8x = 16 + 56
  4. -8x = 72
  5. x = 72 ÷ (-8)
  6. x = -9
5 0
3 years ago
This question is down below. The picture attached below. <br> Thanks.
Ostrovityanka [42]

The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Given an equation showing profits of A Christmas vendor as

P=-0.1g^{2}+30g-1200.

We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.

To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.

665.60=-0.1g^{2}+30g-1200

0.1g^{2}-30g+1200+665.60=0

0.1g^{2}-30g+1865.60=0

Divide the above equation by 0.1.

g^{2}-300g+18656=0

Solving for g we get,

g=[300±\sqrt{(300)^{2}-4*1*18656 }]/2*1

g=[300±\sqrt{90000-74624}]/2

g=[300±\sqrt{15376}]/2

g=(300±124)/2

g=(300+124)/2       , g=(300-124)/2

g=424/2,  g=176/2

g=212,88

Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.

Put the value of P=1500 in equation P=-0.1g^{2}+30g-1200.

-0.1g^{2}+30g-1200=1500

0.1g^{2}-30g+1500+1200=0

0.1g^{2}-30g+2700=0

Dividing equation by 0.1.

g^{2}-300g+27000=0

Solving the equation for finding value of g.

g=[300±\sqrt{300^{2} -4*1*27000}]/2*1

=[300±\sqrt{90000-108000}] /2

=[300±\sqrt{-18000}]/2

Because \sqrt{-18000} comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.

Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.

Learn more about equation at brainly.com/question/2972832

#SPJ1

7 0
2 years ago
Jennifer jogged over to Collin's house last Saturday. She first ran from her house to the lake, which took her 15 minutes. She t
Alexus [3.1K]
Just work the problem in reverse.
1:14pm - 24 minutes would be 12:50pm.
12:50pm - 15 minutes would be 12:35pm.
Jennifer left her house at 12:35pm.
5 0
3 years ago
Explain how you write products when there are not enough digits in the product to place a decimal point
Anni [7]
If you there isn't enough digits to place, just add zeroes to product to make it a full product or don't even use a decimal point at all.
6 0
3 years ago
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